What is the required energy for a projectile to escape Earth?

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SUMMARY

The least initial mechanical energy required for a projectile to escape Earth's gravitational field is determined by the escape velocity, which is 11.2 km/s (or 11200 m/s). The total mechanical energy is the sum of kinetic energy (Ek) and gravitational potential energy (Ep). In scenarios where mass is not specified, the energy can be expressed as 'specific energy times mass', allowing for calculations without needing the exact mass of the projectile. This approach is standard in physics when discussing escape velocity and energy dynamics.

PREREQUISITES
  • Understanding of escape velocity and its calculation
  • Familiarity with kinetic energy (Ek) and gravitational potential energy (Ep)
  • Knowledge of specific energy concepts in physics
  • Basic principles of gravitational fields and forces
NEXT STEPS
  • Study the derivation of escape velocity from gravitational potential energy
  • Learn about specific energy and its applications in physics
  • Explore the relationship between kinetic energy and gravitational potential energy
  • Investigate the concept of gravitational fields and their effects on projectile motion
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Students of physics, aerospace engineers, and anyone interested in the mechanics of projectile motion and gravitational escape dynamics.

mrdrew
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I have a 3 part question, and I have managed to get 2 of the three parts, but I can not figure out the 3rd for the life of me.
A projectile is shot directly away from Earth's surface. Neglect the rotation of Earth. (C) What is the least initial mechanical energy required at launch if the projectile is to escape earth?

I kind of thought i should be using the escape speed of Earth (11.2 km/s or 11200 m/s) and calculate Ek. However, I have no mass, so I'm not quite sure if that's the right way to approach the problem. Any thoughts?

Many thanks!
 
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What is the TOTAL energy of the projectile when it is launched. What is the potential energy of the projectile if it "just reaches" infinity with 0 speed?
 
Yet you still need the mass of the projectile to know total energy.

If the mass is not given, you can provide the answer as a number "times m." But, I'm guessing that perhaps the mass could have been determined from the first part(s) of the question?
 
mrdrew said:
I have a 3 part question, and I have managed to get 2 of the three parts, but I can not figure out the 3rd for the life of me.
A projectile is shot directly away from Earth's surface. Neglect the rotation of Earth. (C) What is the least initial mechanical energy required at launch if the projectile is to escape earth?

I kind of thought i should be using the escape speed of Earth (11.2 km/s or 11200 m/s) and calculate Ek. However, I have no mass, so I'm not quite sure if that's the right way to approach the problem. Any thoughts?

Many thanks!
Yes, you're going the right direction. Total mechanical energy = kinetic plus potential.

As to not having the mass, check your terminology in the book. Usually, if they're talking launches and escape velocity, they're concentrating on how the object moves (acceleration) vs. its 'true' total energy. Since the mass cancels out for acceleration, it's very common for them to talk about 'specific energy' per unit of mass. Either way, if you don't have the mass, the best you can do is express the answer as the 'specific energy times mass'.

m\epsilon
 
im not quite sure i understood exactly what you were referring to when it comes to acceleration of the object. the question in its entirety is here.

a projectile is shot directly away from Earth's surface. Neglect the rotation of Earth. What multiple of Earth's radius Re gives the radial distance a projectile reaches if (a) its initial speed is 0.500 of the escape speed from Earth and (b) its initial kinetic evergy is 0.500 of the kinetic energy required to escape earth? (c) what is the least initial mechanical energy required at launch if the projectile is to escape earth?

i was just thinking, is there a specific distance away from the Earth where a projectile has successfully 'escaped' Earth's gravitational field, or is that mass depenedent as well. If it wasn't, i suppose i could find the gravitational energy at that point and then use to equate it to the necessary kinetic force to get to that distance?
 

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