What is the required wattage to achieve a velocity of 300m/s with 1kg of mass?

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Discussion Overview

The discussion revolves around calculating the required wattage to accelerate a mass of 1 kg to a velocity of 300 m/s, focusing on the relationship between power, energy, and time. Participants explore the implications of different time frames for achieving this velocity while considering Newton's laws of motion.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant asks how many watts are needed to accelerate 1 kg to 300 m/s, excluding factors like friction and drag.
  • Another participant points out that any amount of power can achieve the velocity given sufficient time, indicating a need for clarification on the question's completeness.
  • There is a discussion about whether the same amount of power is required regardless of the time taken to reach the velocity, with one participant expressing confusion about the relationship between power and time.
  • Participants clarify that power is defined as energy per unit time, and the total energy required to reach 300 m/s is 45 kJ, regardless of the time taken.
  • One participant calculates that if the acceleration takes 0.5 seconds, the power required would be 90 kW, while if it takes a year, the power would be approximately 1.4 mW.
  • Another participant expresses confusion over the significant difference in power requirements for the same energy, comparing it to lifting weights at different speeds.
  • Clarifications are made regarding the distinction between energy and power, emphasizing that power depends on the duration over which the energy is applied.
  • Participants discuss the importance of understanding the definitions of terms used in physics to avoid confusion.

Areas of Agreement / Disagreement

Participants generally agree on the distinction between energy and power, but there is some confusion and debate regarding the implications of time on power requirements. The discussion remains unresolved regarding the initial question of how to frame the power calculation without specifying time.

Contextual Notes

There are limitations in the discussion regarding assumptions about initial velocity and the effects of external forces like friction and drag, which are not considered in the calculations presented.

Who May Find This Useful

This discussion may be useful for individuals interested in physics, particularly those exploring concepts of energy, power, and motion, as well as those seeking clarification on the application of Newton's laws.

BilPrestonEsq
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How many watts of power would it take to get a a mass of 1kg up to 300m/s? Leaving out friction, drag, etc.. Just how much power in watts to get 1kg to 300m/s. ??
 
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Your question seems incomplete. Any amount of power can make a 1kg body move at 300m/s, given enough time.
 
...and have you tried using Newton's equations of motion?
 
Doesn't it take the same amount of power to move an object with the mass of 1kg 300m/s regardless of the time it takes? If it took .5 seconds or a year wouldn't it be the same amount of power just over a longer period of time? And yes Newtons laws of motion... I guess that's what I am having trouble with, finding a clear answer to this question. Oh yea and a watt being V*A and an amp being 1 coulomb per*wait* an amp is 1 coulomb passing a GIVEN POINT each second. What does that mean exactly? Arrghh...Man this stuff can get a confusing especially when your biggest teacher is wikipedia.. Help me Physics Forum your my only hope...
 
Watts are joules per second (power=energy/time). Therefore we need to know for how long time the power is applied in order to know the answer to your question.

Doesn't it take the same amount of power to move an object with the mass of 1kg 300m/s regardless of the time it takes? If it took .5 seconds or a year wouldn't it be the same amount of power just over a longer period of time?

No. If it took .5 seconds the power would be 90 kW, if it took a year the power would be about 1.4 mW, assuming constant power and no initial velocity.

I think you're maybe mixing up energy and power? The energy needed to accelerate the object to 300 m/s would be 45 kJ in both cases.
 
Oh 90kw is actually what I got at first and I thought it was wrong. Thanks
 
How is it though that it would take 1.4mw if it is the same energy? That sounds like a lot more energy to me. Isn't that that same as lifting 100lbs in one second compared to lifting in 1min using a pulley. Same energy is used, 90kw vs. 1.4mw doesn't make much sense to me. What equations did you use to find that number? I know I could find it someplace else but I wouldn't be sure I had it right and that's why I joined PF. I appreciate the help.
 
You're mixing up energy and power. The same energy, 45000 Joules, is used in both cases (here i simply used that energy is equal to 0.5*m*v2), but the (average) power is NOT the same!

If the mass is accelerated in .5 seconds, the average power is P = 45000 J / 0.5 s = 90000 W.

If the mass is accelerated in one year, the average power is (60*60*24*365=31536000 seconds in one year) P = 45000 J / 31536000 s = 0.0014 W.

You have to realize that power is a measure of energy per time, not a measure of energy. Therefore the power needed depends on the time the power is applied.
 
Listen to kloptok. Also, keep in mind that colloquial meanings of some words are completely different from what they mean in physics. Always check definitions of actual terms.
 
  • #10
to kloptok I thought you meant 1.4 megawatts .0014watts makes a lot more sense. Thank you guys for answering my stupid questions I am very new to this stuff.
 
  • #11
No no, the prefix m stands for 'milli', 10-3. The prefix for 'mega',106, is a capital M.

Don't be afraid to ask questions, as the saying goes: "There are no stupid questions, only stupid answers".
 

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