What is the Role of Torque in Holding a Sphere Against a Wall?

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Homework Help Overview

The discussion revolves around the role of torque in analyzing the forces acting on a sphere held against a wall by an inclined plane. Participants are exploring the equilibrium conditions and the forces involved in this scenario.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the balance of forces acting on the sphere, particularly the normal forces from the wall and the inclined plane in relation to the weight of the sphere. There is a focus on creating a Free Body Diagram (FBD) and analyzing forces in both x and y components. Questions arise regarding the interpretation of coordinate systems and the application of static equilibrium conditions.

Discussion Status

Some participants have provided guidance on constructing the Free Body Diagram and analyzing forces, while others are clarifying the coordinate system used in the analysis. There is an ongoing exploration of the individual forces rather than their vector sum, indicating a productive direction in the discussion.

Contextual Notes

Participants are working within the constraints of a homework problem that requires a detailed analysis of forces and torque without providing a complete solution. The discussion includes clarifications on terminology and assumptions regarding the setup of the problem.

vibha_ganji
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Homework Statement
A sphere (Fig. 4-31) weighing 50 lbf is leaning against a smooth wall, held there by a smooth inclined plane that forms a 60° angle with the horizontal. Calculate the reaction of the wall and the plane on the sphere. Source: Alonso and Finn Volume 1
Relevant Equations
W = mg
Tau (torque) = r times F
I’m pretty sure that the force on the sphere by the wall and plane has to equal mg so the sum of the normal force is steered by the wall and plane has to equal mg. I’m not sure where to go after this. Is mg the answer or is there something I’m missing?Here is Fig: 4-31:

5600BB9A-480E-48D9-8E2D-30C5FB487A84.jpeg
 
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The vector sum of the force from the wall and the force from the inclined plane is indeed equal (and opposite in order to be more precise since we have vectors) to the vector of weight of the sphere. But the problem statement asks you to calculate the above individual forces not their vector sum.

Make an FBD of the sphere. Choose a coordinate system such that y-axis is the direction of the wall and the x-axis is vertical to it (the horizontal). Analyze all the forces (especially the force of normal from the inclined plane) to x and y components. Finally since the sphere is in equilibrium, apply the static conditions that the algebraic sum all of the x components (of the forces in play) is zero, and also that the algebraic sum of all of the y components is zero as well.
 
Delta2 said:
such that y-axis is the direction of the wall and the x-axis is vertical to it (the horizontal).
You meant "such that y-axis is the direction of the wall (vertical) and the x-axis is normal to it (the horizontal)", right?
 
haruspex said:
You meant "such that y-axis is the direction of the wall (vertical) and the x-axis is normal to it (the horizontal)", right?
yes
 
Tau (torque) = r times F

Do you need this formula ?
 

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