What is the Role of Torque in Holding a Sphere Against a Wall?

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SUMMARY

The discussion focuses on the role of torque in analyzing the forces acting on a sphere held against a wall and an inclined plane. Participants confirm that the normal forces from both the wall and the plane must equal the weight of the sphere (mg) for equilibrium. A Free Body Diagram (FBD) is essential for visualizing the forces and their components. The calculation of individual forces, rather than their vector sum, is emphasized as crucial for solving the problem.

PREREQUISITES
  • Understanding of Free Body Diagrams (FBD)
  • Knowledge of static equilibrium conditions
  • Familiarity with torque calculations (Tau = r × F)
  • Basic principles of forces acting on objects in two dimensions
NEXT STEPS
  • Study the principles of static equilibrium in physics
  • Learn how to construct and analyze Free Body Diagrams
  • Explore torque calculations in detail, including applications in various scenarios
  • Investigate the effects of inclined planes on force distribution
USEFUL FOR

This discussion is beneficial for physics students, engineers, and anyone interested in mechanics, particularly those studying forces and equilibrium in two-dimensional systems.

vibha_ganji
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Homework Statement
A sphere (Fig. 4-31) weighing 50 lbf is leaning against a smooth wall, held there by a smooth inclined plane that forms a 60° angle with the horizontal. Calculate the reaction of the wall and the plane on the sphere. Source: Alonso and Finn Volume 1
Relevant Equations
W = mg
Tau (torque) = r times F
I’m pretty sure that the force on the sphere by the wall and plane has to equal mg so the sum of the normal force is steered by the wall and plane has to equal mg. I’m not sure where to go after this. Is mg the answer or is there something I’m missing?Here is Fig: 4-31:

5600BB9A-480E-48D9-8E2D-30C5FB487A84.jpeg
 
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The vector sum of the force from the wall and the force from the inclined plane is indeed equal (and opposite in order to be more precise since we have vectors) to the vector of weight of the sphere. But the problem statement asks you to calculate the above individual forces not their vector sum.

Make an FBD of the sphere. Choose a coordinate system such that y-axis is the direction of the wall and the x-axis is vertical to it (the horizontal). Analyze all the forces (especially the force of normal from the inclined plane) to x and y components. Finally since the sphere is in equilibrium, apply the static conditions that the algebraic sum all of the x components (of the forces in play) is zero, and also that the algebraic sum of all of the y components is zero as well.
 
Delta2 said:
such that y-axis is the direction of the wall and the x-axis is vertical to it (the horizontal).
You meant "such that y-axis is the direction of the wall (vertical) and the x-axis is normal to it (the horizontal)", right?
 
haruspex said:
You meant "such that y-axis is the direction of the wall (vertical) and the x-axis is normal to it (the horizontal)", right?
yes
 
Tau (torque) = r times F

Do you need this formula ?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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