What Is the Rotational Acceleration in a Revolving Door?

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SUMMARY

The discussion centers on calculating the rotational acceleration of a revolving door that spins once every 4 seconds, increasing to once every second due to a push. The initial angular velocity is determined as 90 degrees per second, leading to a calculated acceleration of 22.5 rev/s². The displacement during the push is calculated as 120 degrees, resulting in a total angular velocity of 140.5 rev/s. The use of linear kinematic principles is suggested to better understand the rotational dynamics involved.

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Homework Statement



Suppose a revolving door at the bank is spinning around once every 4 seconds. As you walk through, you push on the door for 3 seconds, which increases the rotational speed so that it rotates once a second. What wat the rotational acceleration due to your push?

Homework Equations



This is what I have so far...

The Attempt at a Solution



Acceleration-90/4=22.5

Displacement-360/3=120

22.5 + 120= 140.5 rev/s
 
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