What is the rotational inertia of the pole

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Homework Help Overview

The discussion revolves around calculating the rotational inertia of a pole that is balanced vertically and begins to fall. The pole has a specified length and mass, and participants are exploring the appropriate formulas and methods to determine its rotational inertia about a specific axis.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants attempt to apply the formula for rotational inertia using different approaches, questioning whether to use the full length of the pole or its center for calculations. There is also a mention of the Parallel Axis Theorem and its relevance to the problem.

Discussion Status

Some participants have provided calculations and expressed uncertainty about their correctness. Others have referenced a formula from their textbook that may apply to the situation, indicating a potential resolution to the initial confusion.

Contextual Notes

There is a focus on the distribution of mass within the pole and how that affects the calculation of rotational inertia. The discussion also reflects on the need for clarity regarding the axis of rotation and the application of relevant equations.

mybrohshi5
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Homework Statement



A 2.75 m long pole is balanced vertically on its tip. It starts to fall and its lower end does not slip.

the mass of the pole is 12.93 kg

What is the rotational inertia of the pole about an axis through its lower end and perpendicular to the pole?

Homework Equations



I = 1/2mr2

The Attempt at a Solution



I = 1/2(12.93kg)(2.75)2

I = 48.9 kgm2

this was wrong so maybe i thought to use the center of the pole as my R since the mass in distributed throughout the pole


I = 1/2(12.93kg)(2.75/2)2

I = 12.22 kgm2

Does this look right?

thanks for any help
 
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mybrohshi5 said:

Homework Statement



A 2.75 m long pole is balanced vertically on its tip. It starts to fall and its lower end does not slip.

the mass of the pole is 12.93 kg

What is the rotational inertia of the pole about an axis through its lower end and perpendicular to the pole?

Homework Equations



I = 1/2mr2

The Attempt at a Solution



I = 1/2(12.93kg)(2.75)2

I = 48.9 kgm2

this was wrong so maybe i thought to use the center of the pole as my R since the mass in distributed throughout the pole


I = 1/2(12.93kg)(2.75/2)2

I = 12.22 kgm2

Does this look right?

thanks for any help

What does the Parallel Axis Theorem say about how to do this problem?
 
Does your book have a list of moment of inertias for different shapes? And any of those shapes resemble a pole?
 
yeah it says

I = 1/3 m L^2

thank you :) that worked perfectly
 

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