What is the second derivative of a given function with a constant value?

bokche
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Can someone, please, help me solve this math problem?

z" / z = k

z=f(t)

z=?
z" - second derivative of function z=f(t)

k=const.

Thanks
 
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Re write this as z''-kz=0
This is a fairly simple constant coeff. ode, solved with a characteristic polynomial.
If k>0 then you have an exponential solution (two basic solution, one tending to zero and the second grows to infinity)
If k<0 you have an oscillatory motion, with two basic solution being sine and cosine, and the angular frequency being \sqrt{|k|}
 
elibj123 said:
Re write this as z''-kz=0
This is a fairly simple constant coeff. ode, solved with a characteristic polynomial.
If k>0 then you have an exponential solution (two basic solution, one tending to zero and the second grows to infinity)
If k<0 you have an oscillatory motion, with two basic solution being sine and cosine, and the angular frequency being \sqrt{|k|}
And if k= 0, of course, the solution is linear.

(Just wanted to be complete!:smile:)
 
Thanks for replies
Cheers
 
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