What is the significance of the dispersion relation?

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SUMMARY

The dispersion relation is crucial for understanding the relationship between energy and momentum in physical systems. For free electrons in a vacuum, the dispersion relation is defined as \(E=\frac{\hbar^{2}k^{2}}{2m}\), indicating a quadratic relationship between energy and momentum. In contrast, light follows a linear dispersion relation given by \(\omega=ck\). This distinction is significant as it informs the behavior of wave packets, particularly their group velocity, which is defined as \(\vec{v}_g=\vec{\nabla}_k \omega(\vec{k})\). Understanding these relations is essential for applications in semiconductor physics, particularly regarding energy and momentum conservation during light absorption and emission.

PREREQUISITES
  • Understanding of quantum mechanics principles, particularly wave functions.
  • Familiarity with the Schrödinger equation and its applications.
  • Knowledge of energy-momentum relationships in physics.
  • Basic concepts of group velocity and wave packets.
NEXT STEPS
  • Study the implications of the Schrödinger equation in solid-state physics.
  • Learn about the role of dispersion relations in semiconductor physics.
  • Explore the concept of group velocity in various media.
  • Investigate conservation laws in quantum mechanics, especially in photon interactions.
USEFUL FOR

Physicists, quantum mechanics students, semiconductor researchers, and anyone interested in the behavior of particles and waves in various media will benefit from this discussion.

patric44
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what is the significance of the dispersion relation?
hi guys
i would like to know what is the physical significance of the dispersion relation , i know that it relates the energy and momentum vector and correspondingly the energy and momentum with each other , but what does this tell me about the system , and why should i care that the dispersion relation for free electrons in vacuum is given by
$$E=\frac{\hbar^{2}k^{2}}{2m}$$
and for light just ##\omega=ck## , it seems that the electron's energy in vacuum is quadratic in the momentum but what do i gain by knowing that ??
i have too many questions , i will appreciate any help ,thanks .
 
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It tells you how the wave function behaves. Particularly it tells you that a wave packet, which is not too broad in momentum space moves with the group velocity ##\vec{v}_g=\vec{\nabla}_k \omega(\vec{k})##. What do you get for the dispersion relations you mentioned?
 
vanhees71 said:
It tells you how the wave function behaves. Particularly it tells you that a wave packet, which is not too broad in momentum space moves with the group velocity ##\vec{v}_g=\vec{\nabla}_k \omega(\vec{k})##. What do you get for the dispersion relations you mentioned?
since $$\omega(k) = \frac{\hbar*k^{2}}{2m} \;⇒ $$
$$
\left(\frac{\partial}{\partial\;k_{x}}\hat{k_{x}}+\frac{\partial}{\partial\;k_{y}}\hat{k_{y}}+\frac{\partial}{\partial\;k_{z}}\hat{k_{z}}\right)\left[\omega(\vec{k}) \right]= \left(\frac{\partial}{\partial\;k_{x}}\hat{k_{x}}+\frac{\partial}{\partial\;k_{y}}\hat{k_{y}}+\frac{\partial}{\partial\;k_{z}}\hat{k_{z}}\right)\left[\frac{\hbar*\vec{k}.\vec{k}}{2m}\right]
$$
$$\vec{v}_{g} = \frac{\hbar}{m}\left[k_{x}\hat{k_{x}}+k_{y}\hat{k_{y}}+k_{z}\hat{k_{z}}\right]$$
isn't that right
 
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Yes, and that looks pretty familiar for the velocity of a free particle, because what you got is
$$\vec{v}_g=\hbar \vec{k}/m=\vec{p}/m.$$
 
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so the dispersion relation is useful for determining the group velocity of the wave packet inside a medium , i am sorry i have another question , considering an electron moving inside a solid , after solving the Schrödinger equation ,say the following E,k diagram is obtained
gan_bands.jpg

is that complicated diagram just indicate that the electron wave packet is changing its velocity inside the lattice or is there more insight to it
 
patric44 said:
Summary:: what is the significance of the dispersion relation?

hi guys
i would like to know what is the physical significance of the dispersion relation , i know that it relates the energy and momentum vector and correspondingly the energy and momentum with each other , but what does this tell me about the system , and why should i care that the dispersion relation for free electrons in vacuum is given by
$$E=\frac{\hbar^{2}k^{2}}{2m}$$
and for light just ##\omega=ck## , it seems that the electron's energy in vacuum is quadratic in the momentum but what do i gain by knowing that ??
i have too many questions , i will appreciate any help ,thanks .

Well, one thing that could come to mind is "How can I obey both conservation of energy and conservation of momentum for the absorption and emission of light"? This question is highly relevant in semiconductor physics.
 
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