What Is the Smallest Value of k for Given Linear Equations?

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Homework Help Overview

The problem involves finding the smallest integer value of k such that the expressions 1 + k, 1 + 2k, and 1 + 8k equal the numbers 3, 5, and 7, respectively. The context is set within a linear equations framework, and the original poster expresses uncertainty about how to approach the problem.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to solve the equations but feels unsure about their approach. Some participants discuss the validity of the solutions obtained and question whether a solution exists that satisfies all three equations. Others suggest considering alternative mathematical concepts, such as modular arithmetic.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the validity of the equations, but there is no explicit consensus on the correct approach or solution.

Contextual Notes

The original poster notes that this question is intended as a warm-up exercise, which may imply constraints on the complexity expected in the solution. There is also a mention of the teacher describing the question as challenging, leading to further questioning of the assumptions made in the problem.

xdeanna
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If k is an integer and the number 1 + k, 1 + 2k and 1 + 8k are 3, 5 and 7, respectively, then the smallest possible value of k lies in the interval:
A) 0 to 20
B) 21 to 40
C) 41 to 60
D) 61 to 80
E) None

i reallyy don't know how to do this question..school just started 2 days ago and this is just a warm up question my teacher gave us to do..i honestly don't know where to start..if you don't want to give me the full answer, at least start me off..im pretty sure i'll be able to do it :)
 
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ok so i tried something..i think the answer is E but the way i did it seems too easy lol..he said it was a challenging question but none is an option too, right?!

1 + k = 3 --> k=2
1+ 2k= 5 --> k=2
1 +8k= 7 --> k=6/8

so would it be none??..i hate questions like these..i have a feeling its supposed to be a lot harder :s
 
Your work looks fine. If 1 + k = 3, then clearly k = 2. This also works in the second equation, but not the third, so there is no value of k that satisfies all three equations.

Sometimes the hardest part of a problem is coming up with a strategy. Once you have a good strategy, the actual work involved can be easy.
 
Could something mod 10 be going on?
 

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