What is the solution to a nonhomogenous second order differential equation?

  • Thread starter Thread starter jesuslovesu
  • Start date Start date
  • Tags Tags
    Second order
Click For Summary
SUMMARY

The solution to the nonhomogeneous second-order differential equation y'' - 2y' - 3y = -3te^{-t} involves using the method of undetermined coefficients. The correct form for the particular solution Y(t) is At^2e^{-t} + Bte^{-t}, which effectively addresses the nonhomogeneous term -3te^{-t}. The initial attempts with Y(t) = Ate^{-t} and Y(t) = At^3e^{-t} were insufficient, as they did not yield the necessary terms to match the right-hand side of the equation.

PREREQUISITES
  • Understanding of second-order differential equations
  • Familiarity with the method of undetermined coefficients
  • Knowledge of exponential functions and their derivatives
  • Ability to manipulate algebraic expressions involving polynomials and exponentials
NEXT STEPS
  • Study the method of undetermined coefficients in detail
  • Practice solving various nonhomogeneous differential equations
  • Explore the use of the Laplace transform for solving differential equations
  • Learn about the complementary solution for second-order linear differential equations
USEFUL FOR

Students and professionals in mathematics, engineering, and physics who are working with differential equations, particularly those focusing on nonhomogeneous cases.

jesuslovesu
Messages
185
Reaction score
0
[SOLVED] Nonhomogenous Second Order DE

Homework Statement


[tex]y'' - 2y' - 3y = -3te^{-t}[/tex]
Solve

Homework Equations


The Attempt at a Solution



Well first I tried
[tex]Y(t) = Ate^{-t}[/tex]
then
[tex]Y(t) = At^2e^{-t}[/tex]
then
[tex]Y(t) = At^3e^{-t}[/tex]
and
[tex]Y(t) = At^3e^{-t} + Bt^2e^{-t}[/tex]
but I can't seem to get the correct form.

Does anyone know what form I need my Y(t) in order to solve this?
 
Physics news on Phys.org
I believe I end up with a term like
[tex]Ae^{-t} = -3te^{-t}[/tex] which I don't believe I can do anything with?

In fact, in all the cases I've tried I always seem to get something like [tex]Ae^{-t}[/tex] which never cancels out so I can never equation -3te^{-t} to any of my terms
 
Last edited:
ah finally got it with [tex]At^2e^{-1}+Bte^{-1}[/tex]
bah that sucked
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
Replies
3
Views
2K
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 33 ·
2
Replies
33
Views
4K
Replies
3
Views
2K
Replies
9
Views
2K