What is the solution to this transformer problem?

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The discussion revolves around solving a transformer circuit problem, specifically how to find the maximum power and the correct equivalent circuit. Participants clarify the use of the turns ratio (n) and the transformed resistances, emphasizing that the source resistance (R_s) should remain consistent at 20 Ohms. There is confusion regarding the calculated power output, with one user obtaining 115.2 W while the textbook states approximately 10,000 W, leading to questions about the values used for R_s and n. The conversation highlights the importance of correctly interpreting the problem parts and using the appropriate equations for power calculations. Ultimately, the users are seeking clarity on achieving the correct power output as indicated in the textbook.
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Homework Statement



[PLAIN]http://img192.imageshack.us/img192/8428/circuits.png

Homework Equations



\frac{V_L}{V_s} = \frac{nR_L}{n^2 R_s + R_L}

R_s = \frac{R_L}{n^2}

P = \frac{V_L^2}{R_L}

The Attempt at a Solution



How should I go about solving this problem? Do I have to convert it to an equivalent circuit? If so how would the end result look exactly? I haven't seen any good examples in the book of creating equivalent circuits of transformers so I'm a little unsure of what to do.
 
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It looks like n2 is their way of expressing the turns ration of that transformer, 1:n2. So in place of the transformer with 8k in its secondary, you can show a new resistor RS in series with your resistor R, that new resistor bring RL transformed by the square of the turns ratio, as they indicate.
 
NascentOxygen said:
It looks like n2 is their way of expressing the turns ration of that transformer, 1:n2. So in place of the transformer with 8k in its secondary, you can show a new resistor RS in series with your resistor R, that new resistor bring RL transformed by the square of the turns ratio, as they indicate.

In part a) I found n2 to be 10, but how do I find the max power now? I used the equation I posted in the OP to find the load voltage then used P=\frac{V_L^2}{R_L} but I get 115.2 W as power when the book has 10,000 W roughly. Perhaps it's because I use the wrong value for R_s. I used 20 Ohms. Should it be different? Or it could be because of the n value I use. I put in 10.
 
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VitaX said:
In part a) I found n2 to be 10
as do I
but how do I find the max power now?
Are you talking about part (a) or part (b)?
I used the equation I posted in the OP to find the load voltage then used P=\frac{V_L^2}{R_L} but I get 115.2 W as power when the book has 10,000 W roughly.
It can't be thousands of watts. Isn't that a 20 ohm source resistance? So you want the transformed impedances to be of that order, too, so the current from the 120v source is going to be less than 3 amps. (Even were you to short circuit the transformer windings, that 20 ohm will limit the current to 6 amps.)
Perhaps it's because I use the wrong value for R_s. I used 20 Ohms. Should it be different?
I see nothing to indicate a different Rs.
Or it could be because of the n value I use. I put in 10.
In part (b) you are told n1 is 5, and required to find the new n2. So there is no place for using an n of 10.

FWIW, I calculate 1.3125 A is drawn from the 120v supply, in part (b).
 
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NascentOxygen said:
as do I

Are you talking about part (a) or part (b)?

It can't be thousands of watts. Isn't that a 20 ohm source resistance? So you want the transformed impedances to be of that order, too, so the current from the 120v source is going to be less than 3 amps. (Even were you to short circuit the transformer windings, that 20 ohm will limit the current to 6 amps.)

I see nothing to indicate a different Rs.

In part (b) you are told n1 is 5, and required to find the new n2. So there is no place for using an n of 10.

FWIW, I calculate 1.3125 A is drawn from the 120v supply, in part (b).

Yeah I was talking about part a) Apparently some others were able to get the 10,000 W power for part a that was int he back of the book though I couldn't really follow what they did.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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