What is the Speed and Tension of a Swing Ride?

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SUMMARY

The discussion focuses on calculating the tension in the cable and the speed of a swing ride chair using physics principles. The total mass of the chair and occupant is 192 kg, with a cable length of 12.0 m and an angle of 55.5°. The tension in the cable was calculated to be approximately 3322 N, while the correct speed of the chair was determined to be 13.081 m/s after correcting the radius used in the calculations to 12 sin 55.5°.

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  • Understanding of circular motion and forces
  • Familiarity with trigonometric functions, specifically sine and cosine
  • Knowledge of Newton's second law of motion
  • Ability to manipulate equations involving mass, velocity, and radius
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  • Study the principles of centripetal force in circular motion
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keemosabi
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Homework Statement


A "swing" ride at a carnival consists of chairs that are swung in a circle by 12.0 m cables attached to a vertical rotating pole, as the drawing shows. (θ = 55.5°) Suppose the total mass of a chair and its occupant is 192 kg.


(a) Determine the tension in the cable attached to the chair.
N
(b) Find the speed of the chair.
m/s


5-19alt.gif



Homework Equations



Fc = mv^r

The Attempt at a Solution


Ty = Fg
Ty = 9.8 * 192
Ty = 1881.6 N
T = 1881.6/sin 34.5
T = 3321.997

Fc = Tx
Fc = 3321.997 cos 34.5
Fc = 2737.74
Fc = mv^2/r
2737.74 = 192(v^2)/12
v = 13.081

The first part was right but what did I do wrong in the second part?
 
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Hi keemosabi! :smile:
keemosabi said:
Fc = mv^2/r
2737.74 = 192(v^2)/12

erm … 12 isn't the radius. :redface:
 
tiny-tim said:
Hi keemosabi! :smile:


erm … 12 isn't the radius. :redface:

Is it 12 sin 55.5?
 
keemosabi said:
Is it 12 sin 55.5?

yep!
 

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