What is the Speed of Sound in Argon Gas at 30 Degrees Celsius?

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SUMMARY

The speed of sound in argon gas at 30 degrees Celsius is calculated using the formula v = √(γkT/m). In this case, argon is treated as a monoatomic gas with an atomic mass of 40, leading to a calculated speed of sound of 194 m/s. However, the correct value, as indicated by the answer key, is 323 m/s. The discrepancy arises from the incorrect value of the adiabatic index (γ), which should be 5/3 for monoatomic gases, rather than 3/5.

PREREQUISITES
  • Understanding of the ideal gas law (pV = nRT).
  • Familiarity with adiabatic processes and the adiabatic constraint (pVγ = constant).
  • Knowledge of the speed of sound formula (v = √(B/ρ)).
  • Basic concepts of thermodynamics, particularly related to monoatomic gases.
NEXT STEPS
  • Review the derivation of the speed of sound in different gas types.
  • Study the implications of the adiabatic index (γ) in thermodynamic calculations.
  • Explore the properties of monoatomic gases and their behavior under various conditions.
  • Learn about the ideal gas law and its applications in real-world scenarios.
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Students studying thermodynamics, physics enthusiasts, and anyone involved in gas dynamics or related fields will benefit from this discussion.

espen180
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Homework Statement



Determine the speed of sound in argon gas at 30 degrees celsius. Argon is a monoatomic gas with atomic mass 40. Assume adiabatic and ideal gas conditions. The mass of a nucleuon is 1.67*10-27 kg=mp.

Homework Equations



Adiabatic constraint: pVγ=constant.

Ideal gas equation: pV=nRT=NkT

Speed of a sound wave: v=\sqrt{B/\rho}

The Attempt at a Solution



From the adiabatic constraint: \text{d}p V^{\gamma} + \gamma p V^{\gamma-1} \text{d}V=0

B=-V\frac{\text{d}p}{\text{d}V}=\gamma p

Insert into ideal gas equation, using \rho=\frac{Nm}{V} :

B=\frac{\gamma \rho k T}{m}

Finally: v=\sqrt{\frac{B}{\rho}}=\sqrt{\frac{\gamma k T}{m}}

Insert values: m=40*mp=6,68*10-26 kg, k=1.38*10-23 J/K, T=303.15 K, γ=3/5=0.6

This produces the result v=194 m/s.

However, the answer key says the correct value is 323 m/s

I have searched my solution attempt multiple times, unable to find my error. Any help will be greatly appreciated.
 
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espen180 said:
Insert values: m=40*mp=6,68*10-26 kg, k=1.38*10-23 J/K, T=303.15 K, γ=3/5=0.6

γ=Cp/Cv=5/3 for a mono-atomic gas.


ehild
 
Thank you. What an embarrasing mistake. :redface:
 

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