What is the stress within the column?

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SUMMARY

The stress within a marble column with a cross-sectional area of 1.7 m² supporting a mass of 30,000 kg is calculated to be 172,941 N/m². The strain can be determined using the relationship between stress and strain, specifically utilizing the elastic modulus of marble, which is 50e9 N/m². The strain is found to be 3.5e-6 when applying the formula that relates stress to strain through the elastic modulus. This analysis confirms the correct application of fundamental mechanics principles in determining stress and strain in materials.

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Homework Statement



A marble column of cross-sectional area 1.7 m2 supports a mass of 30,000 kg.
(a) What is the stress within the column?
(b) What is the strain?

Elastic modulus for marble E (N/m^2) 50e9
shear modulus (G)

Homework Equations



a)stress=F/A=N/m^2
b) don't know

The Attempt at a Solution



a) 30000*9.8/1.7=172941 N/m^2 (this is right)
b)
 
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The strain will be given by the change in the length of the column divided by its initial length: \frac{\Delta L}{L_0}.

Its relation to the stress is given by: \frac{F}{A} = Y \frac{\Delta L}{L_0}. That is, the stress is equal to the modulus times the strain. Now its just algebra.
 
how do you find the length of the column?
 
You don't need it. You can just treat \frac{\Delta L}{L_0} as a single term, does that make sense?
 
so just solve for that term then? what would Y be? the elastic or shear modulus?

F=30000*9.8
A=1.7
Y=?
 
You would use the elastic modulus, we're speaking in terms of tensile stress and strain. If we were using shear stress and strain, we would use the shear modulus.
 
Last edited:
so-

(30000*9.8/1.7)/50e9=3.5e-6
 
Looks good to me, don't forget to put your answer for part a into significant figures.
 

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