What is the stress within the column?

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Homework Help Overview

The discussion revolves around a physics problem involving a marble column supporting a mass, focusing on calculating stress and strain. The subject area includes mechanics of materials and material properties.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of stress using the formula stress = F/A and explore the relationship between stress and strain through the elastic modulus. Questions about the necessity of the column's length and the definition of the modulus to use are raised.

Discussion Status

Participants have provided guidance on the relationships between stress, strain, and modulus. There is an ongoing exploration of the necessary parameters for calculations, with some participants confirming the correctness of previous calculations while others seek clarification on concepts.

Contextual Notes

There is a lack of information regarding the initial length of the column, which some participants note is not necessary for the calculations being discussed. The problem context is framed within homework constraints, emphasizing the need for significant figures in the final answer.

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Homework Statement



A marble column of cross-sectional area 1.7 m2 supports a mass of 30,000 kg.
(a) What is the stress within the column?
(b) What is the strain?

Elastic modulus for marble E (N/m^2) 50e9
shear modulus (G)

Homework Equations



a)stress=F/A=N/m^2
b) don't know

The Attempt at a Solution



a) 30000*9.8/1.7=172941 N/m^2 (this is right)
b)
 
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The strain will be given by the change in the length of the column divided by its initial length: [tex]\frac{\Delta L}{L_0}[/tex].

Its relation to the stress is given by: [tex]\frac{F}{A} = Y \frac{\Delta L}{L_0}[/tex]. That is, the stress is equal to the modulus times the strain. Now its just algebra.
 
how do you find the length of the column?
 
You don't need it. You can just treat [tex]\frac{\Delta L}{L_0}[/tex] as a single term, does that make sense?
 
so just solve for that term then? what would Y be? the elastic or shear modulus?

F=30000*9.8
A=1.7
Y=?
 
You would use the elastic modulus, we're speaking in terms of tensile stress and strain. If we were using shear stress and strain, we would use the shear modulus.
 
Last edited:
so-

(30000*9.8/1.7)/50e9=3.5e-6
 
Looks good to me, don't forget to put your answer for part a into significant figures.
 

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