What is the tangential acceleration of a toy car at a specific point in a loop?

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SUMMARY

The discussion centers on calculating the tangential acceleration of a toy car at point C, which is located at a height R within a frictionless loop of radius R. The car starts from rest at a height of 4R. The key takeaway is that tangential acceleration is the component of linear acceleration in the tangential direction, distinct from angular acceleration. The Coriolis term, represented as 2\dot{r}ω, is also relevant in this context, although the exact position of point C in relation to the ground remains ambiguous.

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  • Understanding of basic physics concepts, particularly kinematics and dynamics.
  • Familiarity with the definitions of tangential and angular acceleration.
  • Knowledge of gravitational effects on motion in a loop.
  • Basic calculus for interpreting derivatives in the context of acceleration.
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Students studying physics, particularly those focusing on mechanics, as well as educators seeking to clarify concepts related to motion in loops and tangential acceleration.

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Homework Statement


Perhaps I am confused by the concept.
A toy car starts from rest at a height 4R above the ground and continue to a loop of radius R (frictionless). At a point C (height R from the ground) inside the loop, what is the tangential acceleration of the toy car?


Homework Equations



I don't think a=alpha*r is quite relevant to this...or a=dv/dt...

The Attempt at a Solution


not quite yet. perhaps the gravity is the only thing?

Please, explain me of the concept of 'tangential acceleration' and its components.
 
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Tangential acceleration is simply the component of linear acceleration that's in the tangential direction. You are right that this is not the same as angular acceleration * radius, [itex]r\dot{ω}[/itex]. There is also the Coriolis term [itex]2\dot{r}ω[/itex].
It's not quite clear from the question (the position of the loop in relation to the ground is not given): is point C where the loop is vertical?
 

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