What is the trig identity for sin^2x + cos^2x = 1?

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Homework Help Overview

The discussion revolves around the trigonometric identity sin²x + cos²x = 1, with participants exploring its implications and applications in various contexts, particularly in relation to the variable t and its values.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants question how the identity applies when t is not explicitly defined, considering values like π/2 and π. There is exploration of the implications of substituting different variables, such as 2t, and the generality of the identity across different symbols representing angles.

Discussion Status

Some participants provide affirmations regarding the identity's validity regardless of the angle's representation. There is an ongoing exploration of how the identity holds true under various substitutions, though no consensus is reached on the specific application to the problem at hand.

Contextual Notes

Participants note the importance of understanding the identity in the context of circular motion and the implications of different variable substitutions, while also recognizing the lack of explicit definitions for certain variables in the problem statement.

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Homework Statement



Screenshot2012-02-25at20521AM.png


If t = pi/2, then that would equal 2, but they don't say that t = pi/2 so how do they get 2?

Maybe since it's circular motion t = pi, that would work too, but I want to be sure before i move on.
 
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It's a simple trignometric identity.

sin2θ + cos2θ = 1
 
bobsmith76 said:

Homework Statement



Screenshot2012-02-25at20521AM.png


If t = pi/2, then that would equal 2, but they don't say that t = pi/2 so how do they get 2?

Maybe since it's circular motion t = pi, that would work too, but I want to be sure before i move on.

Note the identity sin(kx)^2 + cos(kx)^2 = 1
|v| becomes sqrt(4(1)) = 2
 
What about the 2t? Unless the 2t gets subsumed in the theta and whatever theta is cos^2 and sin^2 add up to 1, is that right?
 
bobsmith76 said:
What about the 2t? Unless the 2t gets subsumed in the theta and whatever theta is cos^2 and sin^2 add up to 1, is that right?

Yes.

If you let u = 2t, then we'd have
sin(u)^2 + cos(u)^2

Which equals 1, and we don't have a "u" to plug back into.
 
bobsmith76 said:
What about the 2t? Unless the 2t gets subsumed in the theta and whatever theta is cos^2 and sin^2 add up to 1, is that right?

Theta is just a symbol for "the argument (or angle) that you pass into the trigonometric function." In this case, the argument to the function is 2t. In other words, θ = 2t here. The identity holds regardless of what theta is. I could have written the identity as:

sin2x + cos2x = 1

OR

sin2ϕ+ cos2ϕ = 1

OR

sin2:smile:+ cos2:smile: = 1

It doesn't matter. All that's changing here is the SYMBOL that I'm using to represent the argument. It doesn't change the meaning of the identity. All of these equations mean the same thing. Expressed in words, the identity is:

"The square of the sine of an angle, plus the square of the cosine of that same angle, together must equal 1."
 
bobsmith76 said:
What about the 2t? Unless the 2t gets subsumed in the theta and whatever theta is cos^2 and sin^2 add up to 1, is that right?
sin2(whatever) + cos2(whatever) \equiv 1.

"Whatever" can be anything, as long as it is the same in both terms.

This is one of the first trig identities presented in a trigonometry course. There aren't many trig identities that you need to memorize, but this is definitely one of them.
 

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