According to relativity mass is invariant because it is the "length" of the energy-momentum four vector (mass-shell condition).
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That's the invariant mass, aka proper mass, aka rest mass.
That is rest mass is what relativity calls "mass".
A theory doesn't call something mass. People do. Some relativists call proper mass "mass" and some relativists call relativistic mass "mass". To understand what I mean by this think of the reason people call the magnitude of a timelike spacetime displacement the
proper time and the time component of that same 4-vector
time. Would you prefer to get rid of the term "proper time" and call that magnitude "time" and then forget about naming the time component? Same thing with a spacelike spacetime displacement. Now consider 4-momentum. The magnitude is
proper mass and the time component is
mass. The magnitude of 4-momentum equals the time component as measured in the rest frame. Why would you want to call the time component something other than mass and then call that same time component "mass" when the frame of reference is just right?
By the way, it is not true that proper mass is defined that way. It would be a circular defintion.
"Mass increasing", "longitudinal and transverse mass" are concepts that come into consideration when one wants to insist on the usual, Newtonian sense of mass, as in the equation F=m a, or one misinterprets the mass-energy equivalence by thinking that it holds for a moving mass, too, thereby attributing speed dependency to mass.
I'm sorry to inform you but that is a common misconception. In the first place it is
very far from being a misconception. Especially if one knows how each term is defined. E = mc
2 does
not define relativistic mass. Far from it. That is a relation which is
derived from the definition of relativistic mass as the m in
p = m
v and the conservation of energy. I.e. m is defined such that
p = m
v is a conserved quantity. For a tardyon m is a function of speed, m = m(v). Proper mass is then defined as m
0 = m(0).
Many relativists (e.g. J.D. Jackson, Hans C. Ohanian, etc) do this in a very similar way. They assume that
p = M
v is a conserved quantity where
p is 3-momentum and
v is 3-velocity. M is assumed to be a function of speed, i.e. M = M(v) where v is the speed of the particle. They then define m = M(0) as the "mass" of the particle. Different strokes for different folks.
Inertial energy E is then defined as the sum of kinetic energy and rest energy. From those two definitions and the derivation of m = gamma*m
0 for tardyon's then the relation E = mc
2 is then
derived. It would be a serious error to think that relativistic mass is defined as m = E/c
2. It has never been defined that way in any serious treatment of special relativity. When Tolman and Lewis first proposed this
definition (and its a definition - note that this is the topic of this thread so far - definition). I.e. Tolman and Lewis defined the mass of a particle to be the m such that p = mv is conserved. All derivations of the relationship for relativistic mass I've ever seen employ this notion.
For the derivation of E = mc
2 for a tardyon see
http://www.geocities.com/physics_world/sr/work_energy.htm
(I use T for E in that page. I like to use E for total energy = kinetic energy + potential energy + rest energy)
This derives E = mc
2 in a manner
similar (not identical) to Einstein's 1905 derivation (mine is clearer).
http://www.geocities.com/physics_world/sr/mass_energy_equiv.htm
Einstein's derivation made no distinction between rest mass and relativistic mass since he used a low speed scenario in which the rest mass = relativistic mass. I do not.
This is a description of Einstein's 1906 derivation
http://www.geocities.com/physics_world/sr/einsteins_box.htm
In the second section of that paper Einstein basically stated that light has mass. This was the first, but not the last, place he did that.
There is nothing Newtonian about
F = d
p/dt. It's as valid in special relativity as it is in Newtonian theory. Many modern texts use it in their relativity sections. It was not Newton who wrote
F=m
a. That was Euler who did that. Newton wrote
F = d
p/dt. The increase in mass (relativistic mass) is not related to any force equation. It is defined and derived soley in terms of momentum. Nothing else whatsoever.
re - "DW answered this." - I don't know what dw wrote. I blocked all his posts due to his past posting habits. i.e. He has a tendacy to ignore all facts given to him and all corrections made against his claims. So I don't bother anymore.
re - "You have answered your own question."
The topic of this thread is the
speed depenance of mass. That means that one is speaking of observing/measuring the mass of a particle in a frame of reference in which the particle is moving, not at rest. Rest mass is the mass as measured in the frame of reference in which the body is at rest. Don't forget, relativity has a lot to do with what different inertial observers measure from different frames of reference. In fact all measurements in the lab are such measurements. E.g. one can measure the relativistic mass of a moving charged particle, of a known charge, by measuring the radius of curvature of its path in a cyclotron. One then uses
p = qBr = mv
or
m = qBr/v
re - "Hmm, relativistic mass increase only has meaning when you are talking about inertial resistance."
That' incorrect. If you've ever read or followed the derivation of the speed depedance of relativistic mass then you'd know that the derivation has nothing to do with force or acceleration. It all has to do with the conservation of momentum. This is what is known as
Weyl's definition of mass. Planck did what you're thinking of in 1906 after Einstein's paper was published. Planck showed that the Lorentz force can be expressed as
F = d
p/dt = q(
E +
vx
B)
where
p = gamma*m
0. That was the first sign in relativity of relativistic mass and, as I recall, Einstein liked it better than his notions in his 1905 paper (but don't quote me on that). However this definition was still connected to electrodynamics. It wasn't until later that the relation was shown to be true apart from electrodyamics. That was done by Tolman and Lewis and it was in a landmark paper. After that paper relativity was brought into the domain of mechanics and out of its restricted domain of electrodynamics (i.e. relativity articles started to be published in mechanics journals etc).
Regarding m is defined such that p = mv is conserved - Pick up any text in which the expression for relativistic mass (or relativistic momentum) is derived and that is what you'll see (E.g. see Jammer's new book on mass). If you don't have a text handy then see
http://www.geocities.com/physics_world/sr/inertial_mass.htm
re - "Otherwise, highly accelerated objects would acquire infinite gravitational attraction and a single proton could gravitationally collapse the entire universe. Obviously, that has not happened."
Do you mean objects with high speed? If so then the faster an object moves the greater is gravitational attraction. See
Measuring the active gravitational mass of a moving object, D. W. Olson and R. C. Guarino, Am. J. Phys. 53, 661 (1985). The faster a body moves the greater its weight too (due to increase in passive gravitational mass). Also, its quite common to see modern GR texts speak of the mass of radiation. Ohanian's text
Gravitation and Spacetime - Second Ed. is one such example.
Note: Sometimes people tend to confuse "invariant" with "independant of the observer." These are not the same concepts. Invariant means "independant of the coordinate system used to evaluate the quantity" whereas "observer independant" means "makes no reference to an observer". E.g. if you take the scalar product the four momentum of a particle with the four velocity of a particular observer, then divide by c
2, you'll get the relativistic mass as measured by that particular observer.
For calculation see bottom of
http://www.geocities.com/physics_world/ma/invariant.htm
The scalar product is an invariant, i.e. it does not matter which set of coordinates you use to evaluate it. A similar thing happens with the electric field. If you take the scalar product of an observers 4-velocity with the EM tensor then you'll get another 4-vector. That 4-vector is called the electric field 4-vector. For this definition see Wald page 64, Eq. 4.2.21 or Thorne and Blanchard's new text (somewhere online - I forget where).
You seem to think I haven't considered all these objections. Not only have considered all these objections but I covered them, and more, in that paper I wrote on the topic of mass in relativity which I posted a link here to several times. However I found many typos an gramatical errors in it and have taken it off line. It will be back on the internet in late fall when I'm better (herniated disk).
Later folks! Have a great summer!
Pete
ps - For those who are interested in this topic see the section on relativistic mass in
Concepts of Mass in Contemporary Physics and Philosophy, Max Jammer. Jammer explains why P
0 = mc where m = relativistic mass. I.e. he argues why that should be the definition of the time component.