What is the unit normal for a cylinder?

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SUMMARY

The unit normal vector for a cylinder defined by the equation x² + y² = 9 can be derived by considering the geometry of the surface. The unit normal vector at any point on the cylinder can be expressed as \(\hat{a}_{n} = \frac{x\hat{x} + y\hat{y}}{\sqrt{x^2 + y^2}}\), ensuring it has a magnitude of 1. This approach is similar to that used for spheres, where the normal vector points radially outward from the origin. Understanding the distinction between unit vectors and general vectors is crucial, as only vectors with a magnitude of 1 qualify as unit normals.

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  • Understanding of vector mathematics and unit vectors
  • Familiarity with the geometric properties of cylinders and spheres
  • Knowledge of vector normalization techniques
  • Basic calculus concepts, particularly gradients
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jeff1evesque
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Homework Statement


The unit normal to a sphere is defined as, \hat{a}_{n} = x\hat{x} + y\hat{y} + z\hat{z}

But I thought it would be defined as, \hat{a}_{n} = 1\hat{x} + 1\hat{y} + 1\hat{z}

Could someone explain to me why am I thinking incorrectly?

Thanks,


JL
 
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If you compute the norm a.k.a. magnitude a.k.a. length of 1\hat{x} + 1\hat{y} + 1\hat{z}, it's \sqrt{3}. So that's not a unit vector.

Is the sphere you're talking about a unit sphere (radius 1)?
 
diazona said:
If you compute the norm a.k.a. magnitude a.k.a. length of 1\hat{x} + 1\hat{y} + 1\hat{z}, it's \sqrt{3}. So that's not a unit vector.

Is the sphere you're talking about a unit sphere (radius 1)?

Yes sir.
 
diazona said:
If you compute the norm a.k.a. magnitude a.k.a. length of 1\hat{x} + 1\hat{y} + 1\hat{z}, it's \sqrt{3}. So that's not a unit vector.

Is the sphere you're talking about a unit sphere (radius 1)?

Yes sir. But I thought the magnitude of the unit vector is a scalar, in which case \sqrt{3} is fine?
 
I believe the top equation is the normal for a general sphere of radius r = Sqrt(x^2+y^2+z^2). The second one is specifically for a unit sphere.

Also, the top equation is not necessarily of unit length. Imagine you had a sphere of radius of 5. The sphere would include the pointing (5,0,0), giving the above vector a magnitude of 5.
 
jeff1evesque said:
Yes sir. But I thought the magnitude of the unit vector is a scalar, in which case \sqrt{3} is fine?
The magnitude of a vector is a scalar. BUT: the magnitude of a unit vector is 1. That's the definition of a unit vector, a vector that has magnitude 1. A vector with any other magnitude is not a unit vector.

As flatmaster said, the magnitude of x\hat{x} + y\hat{y} + z\hat{z} is \sqrt{(x^2+y^2+z^2)}. So x\hat{x} + y\hat{y} + z\hat{z} is going to be a unit normal if and only if \sqrt{(x^2+y^2+z^2)} = 1.
 
diazona said:
The magnitude of a vector is a scalar. BUT: the magnitude of a unit vector is 1. That's the definition of a unit vector, a vector that has magnitude 1. A vector with any other magnitude is not a unit vector.

As flatmaster said, the magnitude of x\hat{x} + y\hat{y} + z\hat{z} is \sqrt{(x^2+y^2+z^2)}. So x\hat{x} + y\hat{y} + z\hat{z} is going to be a unit normal if and only if \sqrt{(x^2+y^2+z^2)} = 1.

what if <br /> \hat{a}_{n} = 1\hat{x} + 1\hat{y} + 1\hat{z}<br />? I don't understand why that would be wrong? Is it because if we take the magnitude then it's not equal to 1? I think i understand now.
 
Last edited:
I guess my question is, how do you get the normal vector \hat{a}_{n} From a sphere with a radius of 1?
 
jeff1evesque said:
what if <br /> \hat{a}_{n} = 1\hat{x} + 1\hat{y} + 1\hat{z}<br />? I don't understand why that would be wrong? Is it because if we take the magnitude then it's not equal to 1?
Yes, exactly.

EDIT: Also, it's not normal to the sphere's surface everywhere.
 
  • #10
Redbelly98 said:
Yes, exactly.

EDIT: Also, it's not normal to the sphere's surface everywhere.

But how do you find the normal? I am reading some stuff, and I notice that the gradient is normal to a surface/curve. If I can find the gradient of our sphere then I can find the normal, and thus the "unit normal". But I am not sure how to find the gradient.
 
  • #11
For this one, we just have to think about the geometry of a sphere. No gradients are necessary.

Any vector that is directed from the origin to some point (x,y,z) on the sphere will be directed along the normal at that point.
 
  • #12
Redbelly98 said:
For this one, we just have to think about the geometry of a sphere. No gradients are necessary.

Any vector that is directed from the origin to some point (x,y,z) on the sphere will be directed along the normal at that point.

That makes much more sense. I totally forgot that the unit normal vector \hat{a}_{n} is a vector beginning from the origin. What if we had a different curve, perhaps a cylinder? Say a problem gave us an equation for a cylinder [namely x^2 + y^2 = 9], along with some arbitrary Force vector. How would we find this unit normal.
Thanks,JL
 

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