Multi-part question involving a vector field

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The discussion revolves around evaluating a vector field at specific points and understanding the concept of unit vectors. The calculations for the vector field at points P(1, 2, -1) and Q(-2, 1, 3) are presented, with corrections made to initial arithmetic errors. Participants clarify that inputting coordinates into the vector field equation yields vectors representing the field's strength and direction at those points, not displacement vectors. A distinction is made between calculating differences in vector field values and finding unit vectors between two points. The conversation concludes with a focus on representing surfaces derived from the vector field equation using graphical tools.
  • #31
CaliforniaRoll88 said:
Is that compatible with windows?
I don’t think so.
 
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  • #32
CaliforniaRoll88 said:
Part d)
##\vec G=24xy\hat a_x+12(x^2+2)\hat a_y+18z^2\hat a_z##
##60^2=(24xy)^2+[12(x^2+2)]^2+(18z^2)^2##
##60^2=24^2x^2y^2+[12x^2+24]^2+18^2z^4##
##60^2=24^2x^2y^2+12^2x^4+2(12x^2)(24)+24^2+18^2z^4##
##60^2=24^2x^2y^2+12^2x^4+24^2x^2+24^2+18^2z^4##
##60^2=6^2[4^2x^2y^2+2^2x^4+4^2x^2+4^2+3^2z^4]##
##100=4x^4+16x^2+16x^2y^2+9z^4+16##
Here is the surface above. It's a bit different from mine but, like I said, I'm learning how to do this.

 
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  • #33
That's awesome. I have my own surface XD. Thank you.
 
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