What Is the Value of Constant k in This Probability Distribution Function?

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Homework Help Overview

The discussion revolves around determining the value of the constant k in a probability distribution function related to the failure of an electrical product over time. The function is defined for a specific time interval and involves an exponential decay component.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss integrating the probability function over a specified interval and equating the result to 1 to find k. There are questions about the correctness of the integral and the dependency of the solutions on the variable t.

Discussion Status

Some participants have provided partial solutions and expressed uncertainty about the steps involved in the integration process. There is acknowledgment of potential errors in reasoning, and one participant has retracted a previous statement, indicating a realization of a mistake.

Contextual Notes

Participants are working with a past exam question and are addressing specific assumptions about the function and its parameters, including the maximum lifespan of the product.

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Homework Statement


The technical specification of a particular electrical product states that the probability of its failure with time is given by the function:

f(t) = 1 - ke^(-t/t0) if 0 < t < tmax
f(t) = 0 if t > tmax

where t is the time of service in years, and the constant t0 = 100 years defines the characteristic deterioration time. If the maximal life span of the product tmax is 10 years,
find the value of constant k , explaining its meaning,

Homework Equations


i thought i was supposed to find the integral of 1 - ke^(-t/t0) with respect to t between 0 and 10 years and put the answer equal to 1. then find k from that. [/B]

The Attempt at a Solution



now this is a past exam paper question so i actually have the partial solution to the question which says that:

k = -9/(t0(e^(-10/t0) - 1))

but what i get is k = -9/(t0e^(-10/t0))

I'm pretty sure I'm doing the integral correctly so there must be some step I'm missing that accounts for that extra -1 in the denominator.

[/B]
 
Last edited:
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Did the past exam question have exactly the same problem statement?
The second solution looks odd. It gives wrong results for very large t0, for example. How did you get it?

Why do both solutions depend on t? They should not do that. Is that tmax?
 
yeah sorry that t should be tmax = 10... I've edited it
 
i just did the integral 0 and 10 of the function given and put it equal to 1 because the probability of it failing within a 10 year period is 100%. once I've done the integral I get:

10 - k*e^(-10/t0)*(-t0) = 1 (int. between 0 and 10 of 1 is 10 and int. between 0 and 10 of k*e^(-t/t0) is k*e^(-10/t0)*(-t0) )

then i find k from that. is this wrong?
 
OMG I just realized what I did! I'm really sorry! never mind! please ignore!
 
i considered e^0 = 0 I've made this mistake quite a few times especially in integrlas! o0)
 

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