What is the vapor pressure of a solution containing glucose and water at 60.0C?

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Discussion Overview

The discussion revolves around calculating the vapor pressure of a glucose and water solution at 60.0°C, specifically focusing on the application of Raoult's law and the determination of molar fractions in the context of a homework problem.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant presents a homework problem involving the vapor pressure of a solution with 0.15 mol of glucose and 1.65 mol of water, noting the vapor pressure of pure water at 60.0°C is 149.38 torr.
  • Another participant confirms that the original poster is on the right track regarding their approach to the problem.
  • A participant inquires about how to find the molar fraction (X) of the solvent.
  • One participant suggests using a formula for molar fraction, emphasizing that the focus should be on the molar fraction of the solvent rather than the solute.

Areas of Agreement / Disagreement

There is no explicit consensus reached among participants regarding the calculation steps, as some questions remain about the determination of the molar fraction.

Contextual Notes

The discussion does not clarify the specific formula for calculating the molar fraction or how to apply Raoult's law in detail, leaving some assumptions and steps unresolved.

beneakin
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Homework Statement


What is the capor pressure of a solution containing .15 mol of glucose (C6H12O6) and 1.65 mol of water at a temperature of 60.0C? the vapor pressure of pure water at this temperature is 149.38 torr


Homework Equations


Ralout's law?

P=PoX


The Attempt at a Solution


im guessing that the P on the left side of the eqn is is VP of pure water(149.38)

im not sure how to get x there is some formula like nsolute/(nsolute + nsolvent)


thanks
 
Physics news on Phys.org
You are on the right track.
 
how do i find X
 
Using formula like the one you have listed, just remember you are looking for molar fraction of solvent, not solute.
 

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