What is the Velocity and Direction of a Puck on an Air Hockey Table?

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SUMMARY

The discussion focuses on calculating the velocity and direction of a puck on an air hockey table using its initial velocity and acceleration components. The initial conditions are defined as v0x = +5.6 m/s, ax = +6.3 m/s², v0y = +9.8 m/s, and ay = -3.6 m/s². To find the magnitude and direction of the puck's velocity at t = 0.50 s, one must calculate the final velocities for both x and y components, then use vector addition to determine the resultant velocity and the angle θ relative to the +x axis.

PREREQUISITES
  • Understanding of kinematic equations, specifically v = u + at
  • Knowledge of vector addition in two dimensions
  • Familiarity with the concepts of velocity and acceleration
  • Basic proficiency in trigonometry for angle calculations
NEXT STEPS
  • Calculate the final velocity components using the equation v = u + at for both x and y directions
  • Perform vector addition to find the resultant velocity of the puck
  • Determine the magnitude of the resultant velocity using the Pythagorean theorem
  • Calculate the angle θ using the arctangent function to find the direction relative to the +x axis
USEFUL FOR

Students studying physics, particularly those focusing on kinematics, as well as educators and tutors seeking to clarify concepts related to motion in two dimensions.

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Homework Statement


A puck is moving on an air hockey table. Relative to an x, y coordinate system at time t = 0 s, the x components of the puck's initial velocity and acceleration are v0x = +5.6 m/s and ax = +6.3 m/s2. The y components of the puck's initial velocity and acceleration are v0y = +9.8 m/s and ay = -3.6 m/s2. Find (a) the magnitude v and (b) the direction θ of the puck's velocity at a time of t = 0.50 s. Specify the direction relative to the +x axis.


Homework Equations


v= u +at
v^2 = U^2 + 2as
s = ut +1/2at^2
s = vt +1/2at^2


The Attempt at a Solution



i don't know how to approach this, in fact i don't even know if I am using the right equations. since there are X and Y component. it would be incorrect for me to find V by only using X or V ... please help.
 
Physics news on Phys.org
If you solve the final velocities for each individual component of the puck's movement you will get two vectors. Using vector additions you can get a resultant….from there you should be able to find the angle relative to the x-axis.
 

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