Finding the Direction of a Puck's Velocity on an Air Hockey Table

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SUMMARY

The discussion focuses on calculating the direction of a puck's velocity on an air hockey table using its initial velocity and acceleration components. The initial x and y components of velocity are given as v0x = +3.3 m/s and v0y = +6.4 m/s, with corresponding accelerations ax = +4.5 m/s² and ay = -3.2 m/s². At t = 0.50 s, the magnitude of the puck's velocity is confirmed to be 7.2 m/s. The correct method to find the direction θ is to use the formula tan(θ) = vy/vx, where vy and vx are the y and x components of the velocity at that time.

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Homework Statement


A puck is moving on an air hockey table. Relative to an x, y coordinate system at time t = 0 s, the x components of the puck's initial velocity and acceleration are v0x = +3.3 m/s and ax = +4.5 m/s2. The y components of the puck's initial velocity and acceleration are v0y = +6.4 m/s and ay = -3.2 m/s2. Find (a) the magnitude v and (b) the direction θ of the puck's velocity at a time of t = 0.50 s. Specify the direction relative to the +x axis


Homework Equations




The Attempt at a Solution


the magnetude v is 7.2 m/s but I cannot find the direction. When i plug into formulas none of my answers are correct: initial y velocity= (7.2) sin θ
 
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welcome to pf!

hi mac227! welcome to pf! :smile:
mac227 said:
the magnetude v is 7.2 m/s but I cannot find the direction.

i don't get 7.2 :redface:

in future, please show your full calculations …

then we can see where you've gone wrong :wink:
initial y velocity= (7.2) sin θ
initial? :confused:

and why not use vy/vx = tanθ ?
 

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