What is the voltage in the inductor or capacitor for a short/open circuit?

AI Thread Summary
The discussion centers on determining the voltages v1 and v2 across a capacitor and inductor at specific time intervals (t=0+ and t=0-). Participants emphasize the importance of knowing the current flowing through the circuit to calculate the voltage across components. There is confusion regarding the steady state condition, as t=0+ is not considered steady state despite the problem's context. The unlabelled resistor value of 3.2 Ω is confirmed as relevant for calculations. Ultimately, the consensus is to find v1 at t=0- and v2 at t=0+ for accurate voltage readings.
sdfanm16
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Screenshot from 2016-05-13 16-37-12.png

Homework Statement



{Moderator edit: The unlabeled resistance is given to be 3.2 Ω }

finding v1 and v2 at t=0+ and t=0- is needed

Homework Equations

The Attempt at a Solution


Screenshot from 2016-05-13 16-43-03.png

ok I've found the currents by mesh analysis but how can i get the voltage?What voltage is in the inductor or capacitor if its a short/open circuit?
Tal
 
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Now you know the current flowing, you can work out the voltage at any point or the voltage across any component. Find the voltage across the capacitor.

Say find the voltage at the RH end of the 3Ω.
Then the junction of the 1Ω Rs
Then at the 1Ω 3Ω junction. Voila.
 
sdfanm16 said:
finding v1 and v2 at t=0+ and t=0- is needed
The subject says: "dc steady state", yet t=0+ is far from steady state. So which are you wanting to find?

You seem to know that the unlabelled resistor is 3.2 Ω?
 
NascentOxygen said:
The subject says: "dc steady state", yet t=0+ is far from steady state. So which are you wanting to find?

You seem to know that the unlabelled resistor is 3.2 Ω?
yes I've forgot to wrote this. it's given.
 
My guess was that you had to find v1 at t=0- when it is stable and to find v2 at t=0+ when it is maximum.
v2 at t=0- is trivial and v1 at t =0+ I would assume is the same as at t=0- , otherwise you would need to know how + t is!
As t →0 both become more accurate.
 

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