The Attempt at a Solution
According to my notes when a circuit is in DC steady state inductors are short circuited and capacitors are open circuited. This leads me to believe that the voltage across the capacitor is basically the voltage looking in through the terminal of the open circuit:
if it's an open circuit then no current flows through R.
(7sin12t - Vc)/R = 0
Vc = 7sin12t
This doesn't seem right to me, can anyone tell me where I'm going wrong?
thanks in advance.