What is the Wind Chill Temperature at 25 mph?

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Homework Help Overview

The discussion revolves around determining the wind chill temperature when the wind is blowing at 25 mph, specifically aiming to find the perceived temperature that feels like 0°F.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss using a table to find perceived temperatures corresponding to actual temperatures, with some suggesting linear interpolation to derive a more precise value. Questions arise about the correct values to use from the table and the method for calculating the slope of the line for interpolation.

Discussion Status

Participants are actively engaging with the problem, exploring different interpretations of the data and calculations. Some guidance has been provided on using linear equations to find the perceived temperature, though there is still uncertainty regarding specific values and calculations.

Contextual Notes

There is mention of a table that provides perceived temperatures based on wind speed, which is central to the discussion. Participants are also navigating potential errors in their calculations and assumptions about the data points used for interpolation.

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Homework Statement


http://img405.imageshack.us/img405/595/tempmq0.th.jpg

If the wind is blowing at 25 mph, approximately what temperature feels like 0°F?


Homework Equations





The Attempt at a Solution




I answered -24 and it's wrong...
What should it be?
 
Last edited by a moderator:
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Yeah, -24 is wrong. Look down the left-most column at the rows for wind speed and find the two numbers in that row that are closest to 0°F perceived temperature. Then look at the top row and find the two actual temperatures the correspond to the two temps you found in the table. You will probably need to do linear interpolation to come up with a single number.

Here's an example. If the question is "the wind is blowing at 10 mph, approximately what temperature feels like 24°F?"
I see in the row for 10 mph the perceived temperatures that bracket 24°F, namely 27°F and 21°F. The actual temps that go with these are 35°F and 30°F. Since my perceived temperature is exactly halfway between the two values in the table, the actual temperature will be exactly halfway between 35°F and 30°F, or 32.5°F.

That's the basic idea. For the linear interpretation I think you'll need to do, you'll have to do a bit more arithmetic than I did, but it ain't "rocket science."
 
so I am looking at the -3 and 4 column which corresponds to a value between 15 and 20?
 
Yes. The value you want will be closer to 15 than 20, since 0 is closer to -3 than it is to 4.
 
and how would I find that value exactly?
 
Use the equation y = mx + b, where x is the perceived temp and y is the actual temp.

You have two points on this line: (-3, 15) and (4, 20). Use these points to find the slope m. Use either point to find b.

When you have the equation of the line, find y when x is 0.

That's one way to do it; there are other ways as well.
 
isn't the point supposed to be (3,15) and (-4,15)
 
They should be (-4, 15) and (3, 20).
 
okay and I found the equation to be :y = 5/7x + 17.85

so therefore the answer is 17.85.. correct?
 
  • #10
Pretty close. 17.86 is closer. The exact value is 17 6/7.
 

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