Triple Integrals with Spherical Coordinates: Finding Limits

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Homework Statement



I have this question about triple integrals and spherical coordinates

http://img405.imageshack.us/img405/9343/81255254.th.jpg



Homework Equations



y = [tex]\rho[/tex] sin [tex]\varphi[/tex] sin [tex]\theta[/tex]
x = [tex]\rho[/tex] sin [tex]\varphi[/tex] cos [tex]\theta[/tex]
z = [tex]\rho[/tex] cos [tex]\varphi[/tex]
[tex]\rho[/tex]2 = z2 + y2 + x2

This is the way
http://tutorial.math.lamar.edu/Classes/CalcIII/TISphericalCoords_files/eq0007MP.gif"

Thus I need to find the limits of integration for [tex]\rho[/tex] [tex]\theta[/tex] and [tex]\varphi[/tex]

The Attempt at a Solution



I used the limits for the z to obtain z2.
Thus, z2 + x2 +y2 = 4
Using the identity for [tex]\rho[/tex]2 = z2 + y2 + x2 then [tex]\rho[/tex]2 = 4
which gives me a value of [tex]\rho[/tex] = 2.

To get [tex]\theta[/tex] I graphed the x limits of the integral. Since x = [tex]\sqrt{4-y<sup>2</sup>}[/tex] then x2 + y 2 =4. Therefore it is a circle of radius 2. Thus I assumed that [tex]\theta[/tex] goes from 0 to 2[tex]\pi[/tex].
Now my problem is to find the limits for [tex]\varphi[/tex] which I don't know how to get.

Any ideas on how to solve for [tex]\varphi[/tex] and also, can someone double check that the other limits of integration are correct?

Thank you!
 
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How do you derive the spherical coordinates? You can find the ranges of [tex]\phi[/tex] in the definition of spherical coordinates, so study your book again! And the ranges for [tex]\rho[/tex] and [tex]\theta[/tex] are correct.
 
rado5 said:
How do you derive the spherical coordinates? You can find the ranges of [tex]\phi[/tex] in the definition of spherical coordinates, so study your book again! And the ranges for [tex]\rho[/tex] and [tex]\theta[/tex] are correct.

Can I use the limits of y to get [tex]\phi[/tex]. For instance since y = 4 then can I say
[tex]\rho[/tex] sin [tex]\phi[/tex] sin [tex]\theta[/tex] = 4 so sin [tex]\phi[/tex] = [tex]\rho[/tex] / sin [tex]\theta[/tex]

Now I am stuck there. Do I plug in a value for [tex]\rho[/tex] and [tex]\theta[/tex]. For instance 2 for [tex]\rho[/tex] and 2pi for [tex]\theta[/tex]. That would give me an undefined answer and sin [tex]\phi[/tex] is always defined. Where do I go from here?
Thank you for the quick response
 
Or since z2 +y2 + x2 = 4 is a sphere and spheres have a [tex]\phi[/tex] from 0 to [tex]\pi[/tex]. Can anybody double check that my limits of integration are correct?

Thank you
 
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Yes your bounderies are now correct and I'm sure about that, because I have a similar example in my book with answer.

[tex]\rho[/tex] is between 0 to 2 and [tex]\theta[/tex] is between 0 to [tex]2\pi[/tex] and [tex]\phi[/tex] is between 0 to [tex]\pi[/tex]