What is the work done by friction on a sliding box?

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SUMMARY

The discussion focuses on calculating the work done by friction on a sliding box with a mass of 12 kg and an initial speed of 10 m/s as it transitions from a smooth surface to a rough surface with a frictional force of 72 N over a distance of 3.0 m. The work done by the frictional force is calculated using the formula Work = Force x Displacement, resulting in 216 Joules. Additionally, the discussion addresses the box's final velocity after leaving the rough surface and the distance required to bring the box to a complete stop.

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tiffanyg
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1. a box of mass 12 kg slides at a speed of 10 m/s acros a smooth level floor, where it enters a rough portion 3.0 m in length. In the rough portion, the box experiences a horizontal friction force of 72N.

a) how much work is done by the frictional force?
b) what is the velocity of the box when it leaves the rough surface?
c) what length of rough surface brings the box coompletely to rest?

Since, I got stuck in the first question...i tried this:

F net= ff+fn
fnet = 72 n+ mg

fnet= 189.6 n

fnet/m = a

a= 15.8 ---> i don't know if a is right...
 
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Ok the first part asks how much work is being done. Work is normally measured in Joules. Try the equation Work = Force x Displacement .
 

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