What is to differentiate under the integral

  • Context: Graduate 
  • Thread starter Thread starter Greg Bernhardt
  • Start date Start date
  • Tags Tags
    Differentiate Integral
Click For Summary
SUMMARY

The discussion focuses on the technique of differentiation under the integral sign, specifically in the context of normalizing Gaussian integrals. By treating a constant as a variable, complex integrals like x² exp(-λx²) can be simplified to the more manageable exp(-λx²). The key equation presented is ∂/∂λ ∫_a^b F(x, λ) dx = ∫_a^b ∂/∂λ F(x, λ) dx, which allows for the transformation of difficult integrals into simpler forms. This method is particularly useful in mathematical physics and statistics.

PREREQUISITES
  • Understanding of integral calculus
  • Familiarity with Gaussian functions
  • Knowledge of partial derivatives
  • Basic concepts of mathematical physics
NEXT STEPS
  • Study the application of differentiation under the integral sign in various mathematical contexts
  • Learn about Gaussian normalization techniques in statistics
  • Explore advanced integral calculus methods
  • Investigate the historical context and applications of Feynman's techniques in physics
USEFUL FOR

Mathematicians, physicists, and students studying advanced calculus or mathematical methods in physics will benefit from this discussion, particularly those interested in integral transformations and Gaussian integrals.

Messages
19,910
Reaction score
10,923
Definition/Summary

The trick is to change a difficult integral into an easier integral by treating a constant as a variable, and integrating with respect to that variable first.

For example, in normalising Gaussians, the difficult integrand [itex]x^2 \exp ( - \lambda x^2)[/itex] where [itex]\lambda[/itex] is a constant can be changed to the easier [itex]\exp ( - \lambda x^2)[/itex]

Equations

[tex]\frac{d}{d\lambda}\int_a^b F(x,\lambda) dx\ =\ \int_a^b \frac{\partial}{\partial\lambda} F(x,\lambda) dx[/tex]

enables us to change a (partial) differential "under" (or inside) the integral sign into an (ordinary) differential outside the integral sign:

So if [itex]f(x,\lambda)[/itex] is difficult to integrate with respect to [itex]x[/itex] but [itex]F(x,\lambda)[/itex] is easier, where [tex]f(x,\lambda)\ =\ \frac{\partial}{\partial\lambda}F(x,\lambda),[/tex]then:

[tex]\int_a^b f(x,\lambda) dx\ =\ \frac{d}{d\lambda}\int_a^b F(x,\lambda) dx[/tex]

Extended explanation

Sometimes we have to normalize Gaussians, and in this case we can use differentiation under the integral sign (as mentioned in "Feymnan's Surely You're Joking, Mr. Feynman!"). Take this example:

[tex] \begin{align*}<br /> \int_{ - \infty }^\infty {x^2 \exp \left( { - \lambda x^2 } \right)} dx = - \int_{ - \infty }^\infty {\frac{\partial }{{\partial \lambda }}\exp \left( { - \lambda x^2 } \right)} dx = - \frac{\partial}{{\partial\lambda }}\int_{ - \infty }^\infty {\exp \left( { - \lambda x^2 } \right)} dx = - \frac{d}{{d\lambda }}\sqrt {\frac{\pi }{\lambda }}<br /> \end{align*}[/tex]

* This entry is from our old Library feature. If you know who wrote it, please let us know so we can attribute a writer. Thanks!
 
Physics news on Phys.org
Using the equation above, we can change the difficult integral x^2 \exp ( - \lambda x^2) into an easier integrand \exp ( - \lambda x^2). The equation states that if f(x, \lambda) is difficult to integrate with respect to x but F(x, \lambda) is easier, then we can use the equation to change the partial differential under the integral sign into an ordinary differential outside the integral sign.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 47 ·
2
Replies
47
Views
5K
  • · Replies 0 ·
Replies
0
Views
1K
  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 18 ·
Replies
18
Views
1K
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
3K