Gabriele Pinna
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What kind of force acts in the centre of the Earth ? What is the intensity ?
If you assume the Earth has a spherically symmetric mass distribution, the gravitational force of the Earth on an object at the center of the Earth would be zero.Gabriele Pinna said:What about the gravitational force acts by the Earth ?
Normal to what?ProfuselyQuarky said:Could you say normal force is acting on the center, or no?
A "normal" force is usually a force between an object and some supporting surface (and normal to that surface). What did you have in mind?ProfuselyQuarky said:Could you say normal force is acting on the center, or no?
Normal meaning orthogonal. I didn’t know there had to be a supporting surface.Doc Al said:and normal to that surface
I had that in mind. I was wondering if that was correct or incorrect. I guess it's incorrect?ProfuselyQuarky said:If we’re talking about a single point in the center of the earth, would that mean that normal force is acting on the point in all directions?
90 degree angle relative to what? Any direction looks the same, there is no normal force because the concept does not even make sense.ProfuselyQuarky said:Normal force meaning any force acting on something at a ##90^{\circ}## (right) angle. If we’re talking about a single point in the center of the earth, would that mean that normal force is acting on the point in all directions?
That is pressure in a fluid, not normal force.ProfuselyQuarky said:would that mean that normal force is acting on the point in all directions?
That’s what I was asking about. Since the 90 degrees would not be relative to any specific surface, I thought that would mean that the force could be acting on the point in all directions.mfb said:90 degree angle relative to what?
Okay, fine. The idea is jargon.mfb said:the concept does not even make sense.
I see . . . thanks for the explanation :)A.T. said:That is pressure in a fluid, not normal force.
I figured that's what you were really inquiring about -- and teasingly avoided that in my first answer. The Doc made good on that, but perhaps it's good to elaborate a bit more. For ##1/r^2## laws such as Newton's law of gravity ( and following ) and Coulomb's law one can derive Gauss' theorem that popularly says: you only have to take into account what's underneath you -- the contributions from the part of the sphere with a greater distance to the center cancel.Gabriele Pinna said:What about the gravitational force acts by the Earth ?