B What kind of force acts in the center of the Earth?

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At the center of the Earth, the gravitational force acting on an object is effectively zero due to the spherically symmetric mass distribution of the Earth, which results in all gravitational pulls canceling out. The discussion also clarifies that the concept of normal force does not apply at this point, as there is no supporting surface to provide a right angle reference. Instead, the pressure experienced at the center is more akin to fluid pressure rather than a traditional normal force. The conversation emphasizes the importance of understanding gravitational forces through principles like Gauss' theorem, which indicates that only the mass beneath an object contributes to gravitational attraction. Overall, the center of the Earth is characterized by extreme pressure and temperature, but not by normal force.
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What kind of force acts in the centre of the Earth ? What is the intensity ?
 
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There is quite some pressure there and it is pretty hot as well.
 
And, of course, the force from the sun according to Newton's law (and from several other celestial bodies...).
 
What about the gravitational force acts by the Earth ?
 
Gabriele Pinna said:
What about the gravitational force acts by the Earth ?
If you assume the Earth has a spherically symmetric mass distribution, the gravitational force of the Earth on an object at the center of the Earth would be zero.
 
Could you say normal force is acting on the center, or no?
 
ProfuselyQuarky said:
Could you say normal force is acting on the center, or no?
Normal to what?
 
Normal force meaning any force acting on something at a ##90^{\circ}## (right) angle. If we’re talking about a single point in the center of the earth, would that mean that normal force is acting on the point in all directions?
 
ProfuselyQuarky said:
Could you say normal force is acting on the center, or no?
A "normal" force is usually a force between an object and some supporting surface (and normal to that surface). What did you have in mind?
 
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Doc Al said:
and normal to that surface
Normal meaning orthogonal. I didn’t know there had to be a supporting surface.
ProfuselyQuarky said:
If we’re talking about a single point in the center of the earth, would that mean that normal force is acting on the point in all directions?
I had that in mind. I was wondering if that was correct or incorrect. I guess it's incorrect?
 
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ProfuselyQuarky said:
Normal force meaning any force acting on something at a ##90^{\circ}## (right) angle. If we’re talking about a single point in the center of the earth, would that mean that normal force is acting on the point in all directions?
90 degree angle relative to what? Any direction looks the same, there is no normal force because the concept does not even make sense.
And a force from what?
 
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  • #12
ProfuselyQuarky said:
would that mean that normal force is acting on the point in all directions?
That is pressure in a fluid, not normal force.
 
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  • #13
mfb said:
90 degree angle relative to what?
That’s what I was asking about. Since the 90 degrees would not be relative to any specific surface, I thought that would mean that the force could be acting on the point in all directions.
mfb said:
the concept does not even make sense.
Okay, fine. The idea is jargon.
A.T. said:
That is pressure in a fluid, not normal force.
I see . . . thanks for the explanation :)
 
  • #14
Gabriele Pinna said:
What about the gravitational force acts by the Earth ?
I figured that's what you were really inquiring about -- and teasingly avoided that in my first answer. The Doc made good on that, but perhaps it's good to elaborate a bit more. For ##1/r^2## laws such as Newton's law of gravity ( and following ) and Coulomb's law one can derive Gauss' theorem that popularly says: you only have to take into account what's underneath you -- the contributions from the part of the sphere with a greater distance to the center cancel.

And it makes sense: along a hole through the Earth something has to happen with the force from gravity, because at the other end it has the same magnitude but points the opposite way.
 
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