What Makes the Wheatstone Bridge Ideal for Measuring Small Resistances?

• fonz
In summary, the wheatstone bridge is a circuit that measures small resistances by providing a zero output voltage when the instrument being measured is at zero. It has virtually no effect on the accuracy and precision of the measurement, and it only becomes useful when the instrument being measured is zero.
fonz
I'm struggling to understand what makes the wheatstone bridge such a good circuit for measuring small resistances. Essentially the bridge is just two voltage dividers and the output voltage is the difference between the two dividers.

Ok so the only advantage I can see over a conventional single voltage divider is that when the instrument being measured is zero, the output voltage will be zero. Which if I am correct is not achievable with a single voltage divider?

So in terms of the accuracy and precision of the measurement at Vout the bridge has virtually no effect it is simply there to provide zero voltage when the instrument is zero?

Thanks

fonz said:
I'm struggling to understand what makes the wheatstone bridge such a good circuit for measuring small resistances. Essentially the bridge is just two voltage dividers and the output voltage is the difference between the two dividers.

Ok so the only advantage I can see over a conventional single voltage divider is that when the instrument being measured is zero, the output voltage will be zero. Which if I am correct is not achievable with a single voltage divider?

So in terms of the accuracy and precision of the measurement at Vout the bridge has virtually no effect it is simply there to provide zero voltage when the instrument is zero?

Thanks

One way to understand is to derive the transfer function of a wheatstone bridge and see how the resistors play a part in the sensitivity. Can you solve for Vout/Vin of a wheatstone bridge? The unknown in the bridge will be proportional to a ratio of two voltages rather than an absolute voltage, and so you can adjust this ratio for sensitivity.

Also, have you seen the term ratiometric before? This is known as a ratiometric measurement. One advantage of ratiometric measurements is that they reduce multiplicative errors.

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DragonPetter said:
One way to understand is to derive the transfer function of a wheatstone bridge and see how the resistors play a part in the sensitivity. Can you solve for Vout/Vin of a wheatstone bridge?

I have seen the equation derived, it makes little sense to me. What I don't understand is that fundamentally you are interested in Vout for a given change in resistance. Why is the equation solved for Vout/Vin? I don't really understand the concept of transfer function to be honest. Is this something that can be put into simple terms?

Thanks

fonz said:
I have seen the equation derived, it makes little sense to me. What I don't understand is that fundamentally you are interested in Vout for a given change in resistance. Why is the equation solved for Vout/Vin? I don't really understand the concept of transfer function to be honest. Is this something that can be put into simple terms?

Thanks

Ya, it can be simplified in terms. Vout and Vin are kind of arbitrary terms, but it means you want to find the output of a circuit when an input is applied, and so you choose the appropriate Vin and Vout.

All you need to do is pick the node on the circuit that has the applied voltage, and then find the node where the voltage is output (the one you are using as a measurement, for example). Solve for the relationship (Vout/Vin) between these two voltages with circuit analysis/algebra, and that gives you your transfer function.

For example in a resistor divider, the Vin is the initial voltage, and the Vout is the voltage after being halved. If you solve for Vout/Vin, you get the transfer function as R1/(R1+R2). The use of this form is that multiplying a transfer function by a Vin voltage will tell you what the output voltage, Vout, is.

Honestly, the best way for you to learn why/how a wheatstone bridge works is to perform the circuit analysis. Substitute your measurement resistor $R$ with "$R + \Delta R$", and see how the output voltage is affected by this $\Delta R$ term, which represents incremental differences in R. Often times circuit analysis is confusing and the results don't always make sense, but when I had to do this for a wheatstone bridge when I studied it, the equations actually made it intuitive of how it works.

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Think old days when meters were analog and power supplies were not stable.
The wheatstone bridge is immune to power supply variations
and it doesn't need an accurate voltmeter, just 3 good resistors.

Zero is very easy to resolve even with primitive instruments.
But no other number is.

1) What is the definition of Wheatstone bridge sensitivity?

Wheatstone bridge sensitivity refers to the ability of a Wheatstone bridge circuit to accurately measure small changes in resistance. It is a measure of how responsive the circuit is to changes in the resistance of one of its arms.

2) How is Wheatstone bridge sensitivity calculated?

Wheatstone bridge sensitivity is calculated by dividing the change in output voltage by the corresponding change in resistance in one of the arms of the bridge. This value is typically expressed as a ratio or percentage.

3) What factors affect the sensitivity of a Wheatstone bridge?

The sensitivity of a Wheatstone bridge is affected by the ratio of the resistances in each arm, the type and quality of the bridge components, the voltage source, and any external factors that may cause noise or interference in the circuit.

4) How can the sensitivity of a Wheatstone bridge be improved?

The sensitivity of a Wheatstone bridge can be improved by using precision resistors, a stable voltage source, and minimizing external interference. Additionally, using a higher ratio of resistances in the arms of the bridge can increase sensitivity.

5) How does Wheatstone bridge sensitivity affect the accuracy of measurements?

The sensitivity of a Wheatstone bridge directly affects the accuracy of measurements. A higher sensitivity allows for more precise and accurate measurements of small changes in resistance, while a lower sensitivity may result in less accurate readings.

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