What Mistake Am I Making in This Limit Calculation?

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SUMMARY

The discussion centers on the limit calculation of the expression as x approaches positive infinity: limx→∞ (x + r(x2 + 2x)). The user attempts to simplify the expression by multiplying by the conjugate but encounters an undefined result leading to 2/0. The key issue arises from the lack of clarity in the expression due to missing brackets, which obscures the intended mathematical operations. Clarification on the value of r (whether it is positive, negative, or zero) is essential for accurate limit evaluation.

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Homework Statement



limi as x-> positive infinity x+r((x^2)+2x)


The Attempt at a Solution



multiply by conjugate x-r((x^2)+2x)

I get (x^2)-(x^2)+2x/x-r((x^2)+2x)

Which becomes 2x/x-r((x^2)+2x)

Which I end up with 2/1-r(1-(2/x))


But I go wrong somewhere because I end up with 2/0 and the answer is positive infinity. I keep getting undefined and I can't see where I'm going wrong. Could someone point it out?
 
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kLPantera said:

Homework Statement



limi as x-> positive infinity x+r((x^2)+2x)


The Attempt at a Solution



multiply by conjugate x-r((x^2)+2x)

I get (x^2)-(x^2)+2x/x-r((x^2)+2x)

Which becomes 2x/x-r((x^2)+2x)

Which I end up with 2/1-r(1-(2/x))


But I go wrong somewhere because I end up with 2/0 and the answer is positive infinity. I keep getting undefined and I can't see where I'm going wrong. Could someone point it out?

What is r? Is it a number, a function, or what? If it is a number > 0 you should have no trouble saying what is ## lim_{x \rightarrow \infty} x + r(x^2 + x).## If r is a number < 0 it is almost as easy, but you need to be careful. And, of course, if r = 0 it is easier still.

I have no idea why you would want to take conjugates, and anyway, I stopped reading your work because you have not used brackets I cannot tell whether you mean
x^2 - x^2 + \frac{2x}{x} - r(x^2 + x), (which IS the meaning of what you wrote) or whether you mean
x^2 - x^2 - \frac{2x}{x - r(x^2 + 2x)}
or
x^2 - \frac{x^2 + 2x}{x - r(x^2 + 2x)},
or several other possibilities.

RGV
 

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