What rate does water flow through the pipes?

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SUMMARY

The discussion focuses on calculating the mass flow rate of water through a horizontal pipe system with varying diameters. Using Bernoulli's equation, the pressure difference between the larger pipe (7.50×104 Pa) and the smaller pipe (5.70×104 Pa) is analyzed to determine the flow rate. The user derived the velocity difference and attempted to find the mass flow rate using the formula m = Avρ, where A represents the cross-sectional area and ρ is the water density (1000 kg/m3). The final calculations suggest a mass flow rate of approximately 68644 m3/s, although the user expressed uncertainty regarding the accuracy of their units and calculations.

PREREQUISITES
  • Understanding of Bernoulli's equation and its applications
  • Knowledge of fluid dynamics principles
  • Familiarity with calculating cross-sectional areas of pipes
  • Basic algebra and unit conversion skills
NEXT STEPS
  • Review Bernoulli's equation and its derivations in fluid mechanics
  • Learn how to calculate mass flow rate using the continuity equation
  • Explore the concept of pressure drop in pipe systems
  • Investigate the effects of pipe diameter changes on flow rates
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Students studying fluid dynamics, engineers working on hydraulic systems, and anyone involved in the design or analysis of piping systems.

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Homework Statement



A horizontal pipe 10.9 cm in diameter has a smooth reduction to a pipe 4.50 cm in diameter. If the pressure of the water (density = 1000 kg/m3) in the larger pipe is 7.50×104 Pa and the pressure in the smaller pipe is 5.70×104 Pa, at what rate (as mass per unit time) does water flow through the pipes?

Homework Equations



Bernoulli's equation. Po+1/2(rho)v^2+(rho)gh= pfinal +1/2(rho)vfinal^2+(rho)(g)(h final)

The Attempt at a Solution


if i sub in the necessary parts we know that h will be the same so that becomes a constant. Po is 7.50×104 Pa and Pfinal is 5.70×104 Pa so if we simploify the above equation we get P1-P2 = ½\rhov22-½\rhov12.so i solved for \Deltav by \sqrt{\frac{P1-P2}{0.5*\rho}} i got an answer of 6 but am unsure of the units to put in the answer..if this is actually the right working..pls. help
 
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The rate of flow of water can be written as
m = Avρ
m^2 = A^2*v^2*ρ^2
1/2*m^2/A^2*ρ = 1/2*ρ*v^2
Substitute this value in the equation to find m.
 
i'm a little confused what value am i substituting in the equation to find m??and if i use the equation 1/2*m^2/A^2*ρ = 1/2*ρ*v^2

(m2/A2)*(1000)= (1000)v2

would my A= sum of both pipes diameter ...and what would v equal?l
 
P1 - P2 =1/2*ρ*v2^2 - 1/2*ρ*v1^2 = 1/2*m^2/ρ*(1/A2^2 - 1/A1^2)
 
P1 - P2 = 1/2*m^2/ρ*(1/A2^2 - 1/A1^2)
delta p =18000
A1= 9.331x10^-3
A2= 1.5904 x10^-3

i sub it in and get a value of 137030.15 ..does that look right??
 
I am getting 68644 m^3/s
 

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