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What size does electromagnet has to be to imitate the power of neodymium magnet?

  1. May 2, 2012 #1
    Hello all,

    I am interface designer that occasionally steps out and does some product/concept design. The last one im working on is something that would require me to make a matrix of little electro magnets, and i am just starting to inform my self about all that. I loved electrical engineering and physics when i was in elementary school and high school but afterwards in college unfortunately i grew apart from it because of the other interests i developed.

    For the project im playing with right now i used 1x1x1cm neodymium magnet for experimenting, and it did job just perfect, i tried bigger i tried smaller, but this one is perfect.
    The problem is that i need an electromagnet to do the same thing in future. (probably lots of them)

    The question is, how large does an electromagnet needs to be in volume to have the same/similar power as neodymium magnet sized 1x1x1cm.
    Or even better question, how small can it be, because i really need it small but powerful :)

    The point of the question is just for me to hear someone experienced on the subject with some theoretical answer (Because i assume it will be enough for this stage of exploration). The real work will be done in collaboration with some professional guy just like you that i will look for if i decide to dive into all this.

    Now i am aware of the fact that there are probably different ways you can measure one magnets strength, and that not all neodymium magnets are same so it cant be treated as a constant, but i would just like to know in general, is it like 2ccm electromagnet or is it like 20ccm electromagnet.

    I hope this post is not too long, and really looking forward to some answers i can get here.
    btw, i am very sorry if i missed the forum my guess was it belongs here, even though after searching the forum i found some stuff concerning this (but not an answer) in "general physics"

    Thanks a lot in advance
  2. jcsd
  3. Jun 4, 2013 #2
    do you already know the answer?
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