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how do i solve this equation with both sinβ and cosβ, i realise that i need to play with the identities but have had no luck,

please help

i tried squaring the whole thing, and saying cos

^{2}β=t,

then i get

0.023556=0.02t - 0.582[tex]\sqrt{t-1}[/tex][tex]\sqrt{t}[/tex] +0.08468t*(1-t)

then i have to square again to get rid of the rooy, but it seems to never end,

how else can i solve this to findβ