- #1

seanoe25

- 7

- 0

2.) I'm looking at the trig identity sin^2 x+cos^2 x=1, and am wondering if I could use that in solving the problem. Or should I use u=sin x, then du= cos x, then plug those in?

3.) so I thought maybe it would be easier to separate the two integrals. I came up with

7∫sin (x)*dx + ∫[1+cos^2(x)]^-1*dx.

which equals

7 cos (x)dx+∫1/[1+cos^2(x)]

u=sin(x)

du=cos(x)*dx

= ∫dx/[1+du^2]

And now I'm stuck. Please help