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## Homework Statement

A truck weighing 3.0*10^4 newtons was driven up a hill that is 1.6*10^3 meters long to a level area that is 800 meters above the starting point. If the trip took 480 seconds, what was the minimum power required?

## The Attempt at a Solution

My problem here is to find out the total work. I know that the work done by vertical position and along the hill is the same, and then divided by the time, so to get power. But I tried to use W=PE+KE, but it didn't come out the same answer. I used: PE=mgh=3.0*10^4*800, KE=1/2mv^2=1/2*30000/9.81*1600/480. then i added them up and divided by 480. It just didn't come out right. I dont know why i can't use this method?