What Wavelength of Light is Needed to Ionize an Electron at n=2 in Hydrogen?

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To ionize an electron at n=2 in a hydrogen atom, one must calculate the energy required to remove the electron from this excited state. The relevant equations include E=hc/λ and the energy difference formula for hydrogen. Ionization refers to the removal of an electron from an atom, which in this case involves determining the energy needed to fully remove the electron from the n=2 orbital. This energy can then be converted into the corresponding wavelength of light. Understanding these concepts is crucial for solving the problem effectively.
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What wavelength of light ,λ, would be necessary to ionize an electron at n = 2 in a hydrogen atom?

In my notes there are two equations that seem relevant to my question they are:

E=hc/λ and -2.18 x 10-18 J((Z^2/n final^2)-(Z^2/n initial^2))

where h is planks constant, c is the speed of light, Z is the atomic number of the element, in my case hydrogen, and n is the state the electron is in. I think it means energy state.

I tried to think of something, but I don't know. What does it mean by ionizing an electron??
 
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Julian Rose said:
...I tried to think of something, but I don't know. What does it mean by ionizing an electron??

It should have been worded "ionizing a hydrogen atom", as ionization is defined as the removal of an electron from an atom or molecule. So your question asks you to calculate how much energy does it take to completely remove an electron from hydrogen that has its electron already excited to the n=2 orbital and then convert that energy into a wavelength of light.
 

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