What Went Wrong with This Linear Temperature Scale Problem?

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Homework Help Overview

The problem involves converting a temperature from Kelvin to a linear temperature scale X, where specific boiling and freezing points of water are given. The context is rooted in thermodynamics and temperature scales.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the slope for the conversion between the temperature scales using given boiling and freezing points. Some participants question the accuracy of the slope calculation and its application in the formula.

Discussion Status

The discussion has seen attempts to clarify the calculation of the slope and its implications for the conversion. One participant has acknowledged a mistake in their calculations, indicating a productive direction in resolving the issue.

Contextual Notes

There appears to be confusion regarding the correct interpretation of the slope and its units, as well as the accuracy of the calculations performed. The original poster's reliance on an online homework system adds a layer of complexity to the discussion.

jdawg
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Homework Statement



I'm not sure what I'm doing wrong on this problem! Please help :)

Suppose that on a linear temperature scale X, water boils at -40.0°X and freezes at -174°X. What is a temperature of 146 K on the X scale? (Approximate water's boiling point as 373 K.)

Homework Equations





The Attempt at a Solution



(K1,X1)=(373, -40)
(K2,X2)=(273, -174)

m=(X2-X1)/(K2-K1)=0.74627 X per K

X-X1=m(K-K1)
X=0.74627K-238.358
X=0.74627(146)-238.358
X= -129.4
 
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For m, I get 1.34.

Chet
 
I tried plugging in that slope into the formula and my online homework wouldn't accept the answer I got. Is the slope not X/K?
 
Never mind, I messed up when I entered it into my calculator! Thanks so much!
 

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