Is Snell's law incompatible with interface conditions? What went wrong?

In summary, the problem is that Snell's law does not seem to hold when applied to the transmitted wave (calculated using the electromagnetic interface conditions). This is likely because the reflected wave is not taken into account.
  • #1
64
1
Hi everyone,

Someone posted this hypothetical problem on a facebook group and I am wondering what your thoughts are.

The issue is that Snell's law does not seem to hold when applied to the transmitted wave (calculated using the electromagnetic interface conditions.) Here is an example:

Suppose we have an interface at y=0 between vacuum (medium 1; n1 = 1) and a material of εr = μr = 10 (medium 2; n2 = 10).

246059

For a plane electromagnetic wave whose electric field is given by the green arrow, we subsequently have:

246061

And a propagation direction along E1xH1:
246062


which corresponds to an angle of 36.87 degrees.

Using the interface conditions, we find that in the second medium, E2 has a unit vector of (x+ 0.132y), and that H2 is in a direction identical to H1 (i.e. z).
This gives rise to a propagation direction of
k2 = -0.132x + y

Which corresponds to an angle of 82.47 degrees.

Now the problematic issue is:
sin(theta2) / sin(theta1) = sin(82.47)/sin(36.87) = 1.65
Whereas
n1/n2 = 1/10 = 0.1.

Doesn't Snell's law stipulate that they're equal? What went wrong?
 

Attachments

  • 1562145031575.png
    1562145031575.png
    2.9 KB · Views: 253
  • 1562147264538.png
    1562147264538.png
    958 bytes · Views: 249
Science news on Phys.org
  • #2
I don't understand how you determined E2 and H2: "Using the interface conditions, we find that in the second medium, E2 has a unit vector of (x+ 0.132y), and that H2 is in a direction identical to H1 (i.e. z). "
 
  • #3
Hi Andy,
E1 = 5V/M * [0.6,0.8] = [3,4,0] V/M
Using the conditions for continuity at the interface:
E2x = E1y = 3
E2y = E1y * (epsilon1/epsilon2) = 4 * 1/10 = 0.4
So E2 = [3, 0.4, 0] V/M
= 3.02 V/M * [ 0.991, 0.1321, 0 ]
For H2,
H1 = [0,0,5/377] A/M Hence H2z = H1z * meu1/meu2 = 0.5/377 A/M

(This got me even wondering, how does the continuity stipulate that H1z = H2z = 5/377 A/M, when due to propagation we require H2z = 3.02/377 A/M!)
 
Last edited:
  • #4
One error: n = √(ε_r μ_r), so if n = 10 and μ_r = 1 (valid for dielectrics), then ε_r = 100.
 
  • #5
Andy Resnick said:
One error: n = √(ε_r μ_r), so if n = 10 and μ_r = 1 (valid for dielectrics), then ε_r = 100.
For the second medium, εr = μr = 10
 
  • #8
Did you consider the reflected wave?
 
  • #9
DrDu said:
Did you consider the reflected wave?
Thanks! that was probably it!
 

Suggested for: Is Snell's law incompatible with interface conditions? What went wrong?

Replies
1
Views
1K
Replies
23
Views
2K
Replies
1
Views
1K
Replies
54
Views
4K
Replies
19
Views
4K
Replies
7
Views
1K
Replies
3
Views
1K
Back
Top