What Went Wrong with This Linear Temperature Scale Problem?

[jdawg]

Homework Statement

I'm not sure what I'm doing wrong on this problem! Please help :)

Suppose that on a linear temperature scale X, water boils at -40.0°X and freezes at -174°X. What is a temperature of 146 K on the X scale? (Approximate water's boiling point as 373 K.)

Homework Equations

The Attempt at a Solution

(K₁,X₁)=(373, -40)
(K₂,X₂)=(273, -174)

m=(X₂-X₁)/(K₂-K₁)=0.74627 X per K

X-X₁=m(K-K₁)
X=0.74627K-238.358
X=0.74627(146)-238.358
X= -129.4

 

[Chestermiller]

For m, I get 1.34.

Chet

 

[jdawg]

I tried plugging in that slope into the formula and my online homework wouldn't accept the answer I got. Is the slope not X/K?

 

[jdawg]

Never mind, I messed up when I entered it into my calculator! Thanks so much!