What if Gauss' Law was(adsbygoogle = window.adsbygoogle || []).push({});

div(E)=q^{2}/eps_{0}

Then if we had two point charges, how could we calculate the resultant E field at an arbitrarily point? Obviously superposition would not work anymore, so how could it be done mathematically?

This is essentially a math question

**Physics Forums - The Fusion of Science and Community**

# What would E field addition be if Gauss's law was different

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

Have something to add?

- Similar discussions for: What would E field addition be if Gauss's law was different

Loading...

**Physics Forums - The Fusion of Science and Community**