1. You have a mass hanging off of a frictionless pulley (massless string). The other mass is on a table. The weight of the mass causes the block on the table to slide at an acceleration. There is friction between the block and the table. What would the coefficient of kinetic friction be for this set up? 2. F = ma w = mg 3. Well Since the system is accelerating, I thought it was T(rope) - fk = ma Acceleration and the masses are known. T isn't. But you can set this up for both masses T(rope) - ukm1g = m1a T(rope) - m2g = m2a T(rope) = m2g + m2a m2g + m2a - ukm1g = m1a -ukm1g = m1a -m2a - m2g -uk(0.483)(10) = 0.483(1.66) - 0.25(1.66) - 0.25(10) uk = 0.438 Does this make sense?