What's the difference between the Riemann & Darboux Integrals?

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SUMMARY

The Riemann and Darboux integrals, while having different definitions, are equivalent in their outcomes. The Darboux integral utilizes upper and lower sums, whereas the Riemann integral employs a mean value approach. Frederic Riesz elaborates on this equivalence in "Leçons d'analyse functionelle." Notably, the Darboux integral encompasses a broader class of functions, as it can integrate functions that the Riemann integral cannot.

PREREQUISITES
  • Understanding of integral calculus concepts
  • Familiarity with Riemann integrals
  • Knowledge of Darboux integrals
  • Basic grasp of functional analysis
NEXT STEPS
  • Study the definitions and properties of Riemann integrals
  • Explore the concepts of upper and lower Darboux integrals
  • Read Frederic Riesz's "Leçons d'analyse functionelle" for in-depth analysis
  • Investigate the relationship between Riemann and Lebesgue integrals
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Mathematicians, students of calculus, and anyone interested in the foundational concepts of integration in mathematical analysis.

swampwiz
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I was reading about this, and they seem the same. Of course, if they were the same, they wouldn't have different names.
 
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Riemann integrals and Darboux integrals have different definitions. However they are equivalent.
 
One of the two authors, Frederic Riesz, describes the question in detail in points 10 and 13 of Chapter I of the book by F. Riesz and B. Sz. Nagy, Leçons d'analyse functionelle.

There are two types of Darboux-integrals: upper and lower. These integrals belong to two interval functions

$$(\beta-\alpha) \sup_{\alpha \leq x \leq \beta} f(x), ~~~~~ (\beta-\alpha) \inf_{\alpha \leq x \leq \beta} f(x). $$
If the first interval function can be integrated, then we are talking about the upper Darboux-integral, if the second, then the lower Darboux-integral. Maybe both exist, perhaps just one, possibly none.

In cases where both exist and are even equal, it is said that the function can be integrated in the Riemann sense. So Darboux's integrals have much more functions than Riemann's integrals.
 

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