What's the recoil energy in optical lattice?

Jason Wang
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Will anyone give me an explanation helping me understanding it?
 
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The recoil energy is p2/2m, where p=h/λ is the momentum of a lattice photon and m is the mass of an atom or ion trapped in the lattice.

The recoil energy is the kinetic energy an atom (or ion) would have after emitting a photon, if initially at rest.
 
Hi,
Recoil energy E=Mv2/2=p2/(2M)=Ep2/(2Mc2)=(\hbark)2/(2M).
M=mass of something (nucleus, atom, ion, etc), which emits photons.
v=recoil velocity due to emission of photons.
p=momentum.
Ep= Energy of the emitted photons.
c=velocity of light in vacuum.
k=wave vector.
 
Redbelly98 said:
Welcome to Physics Forums.

The recoil energy is p2/2m, where p=h/λ is the momentum of a lattice photon and m is the mass of an atom or ion trapped in the lattice.

The recoil energy is the kinetic energy an atom (or ion) would have after emitting a photon, if initially at rest.



I see, Thanks a lot
 
Rajini said:
Hi,
Recoil energy E=Mv2/2=p2/(2M)=Ep2/(2Mc2)=(\hbark)2/(2M).
M=mass of something (nucleus, atom, ion, etc), which emits photons.
v=recoil velocity due to emission of photons.
p=momentum.
Ep= Energy of the emitted photons.
c=velocity of light in vacuum.
k=wave vector.



It helps
 

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