Wheatstone Bridges: Which Has Greater Static Sensitivity?

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In comparing two Wheatstone bridge circuits with fixed resistors of 100 ohms and 25 ohms, the lower resistance bridge is expected to exhibit greater static sensitivity. Static sensitivity is defined as the ratio of output voltage change to input change, indicating how responsive the circuit is to variations. Both bridges are balanced, but the lower resistance configuration will produce a larger output voltage change for the same input change due to its reduced resistance. This makes the 25-ohm bridge more effective for applications requiring precise measurements. Ultimately, the choice of bridge impacts the sensitivity and accuracy of voltage readings in practical scenarios.
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Say I have two Wheatstone bridge circuits: On each of them, the top half of the diamond is formed using two fixed resistors. The bottom half of each diamond consists of a variable resistor on the left and a resistance temperature detector on the right. Now, for the first bridge circuit, the two fixed resistors are each 100 ohms, while for the second, they are 25 ohms. Both bridges operate in balanced bridge mode.

Which bridge circuit has the greater static sensitivity?

I know that the bridge is balanced when the ratio of the two top resistors equals the ratio of the two bottom resistors... but this equals 1 in both cases.

My guess is that the lower resistance bridge circuit is more sensitive to changes in voltage, so then it would be the obvious choice. Can anyone confirm this?
 
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What is the definition of the static sensitivity? You should end up in units of input to output. So, for instance, if you were measuring pressure, your static sensitivity would be in units of psi/mV or something along those lines.

So in other words, which bridge will create more of a change in output voltage per unit of input?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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