Undergrad When can I treat a joint as a fixed conection?

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A joint can be treated as a fixed connection under certain conditions, even if it cannot transfer moments, as long as external forces are applied correctly. The discussion highlights that using internal forces within the joint can yield accurate results while maintaining the same pivot point. The pivot point is defined as the location below the 10kg beam where it balances and remains horizontal. The scenario assumes that the system is not floating in space, and the 100kg box can separate from the 10kg box. Understanding these dynamics is crucial for accurate mechanical analysis.
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Question is : is pivot point is both case at same position...

Useing only external forces (100kg,10kg and 30kg) I can treat joint as fixed conection and still get correct results,in both case pivot point is at same positon,even right case has joint at right side of beam..
How is possible that I treat joint as fixed conection and still get correct result,isnt this confusing becasue joint can't trasnfer moment ,only forces?When I can't treat joint as fixed conection?
Because joint can't trasfer moment only forces,so I can use internal forces inside joint and still get same results,pivot point is at same position in both case..
 
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John Mcrain said:
Question is : is pivot point is both case at same position...
View attachment 278592
Define "pivot point " mathematically.
Is the whole thing floating in space?
Is the 100kg box free to separate from the 10kg box?
 
A.T. said:
Define "pivot point " mathematically.
Is the whole thing floating in space?
Is the 100kg box free to separate from the 10kg box?

no in space,yes it can separate..
Pivot point is point below 10kg beam so beam is balance,stay horizontal..

jiojo.jpg
 
Hi, I'd ask for clarification about some topics on angular momentum calculation. Consider a system of particles moving w.r.t. a given inertial frame ##\mathcal A##. Picked a point ##P## in ##\mathcal A## one defines the angular momentum vector ##\vec L## w.r.t. the reference point/pole P. Furthermore one defines the axial angular momentum ##L_a## as the component along ##a## of the system's angular momentum ##\vec L## calculated w.r.t. a pole ##P## on the axis ##a##. Such a notion is well...

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