When does the collision occur and at what height?

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Homework Help Overview

The problem involves a ball in free fall and an arrow being shot at it, with the ball starting at a height of 38 m above the arrow. The discussion focuses on determining the time of collision and the height at which it occurs, considering both scenarios with and without air resistance.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the application of equations of motion and the effects of air resistance on both the ball and the arrow. There is uncertainty about whether to include drag force for the arrow and how to set up the equations correctly.

Discussion Status

Some participants have attempted to solve the problem and have reached a quadratic equation, while others are questioning the inclusion of drag force on the arrow. There is a suggestion to use the quadratic formula to find the time of collision, indicating that the discussion is exploring various approaches.

Contextual Notes

Participants note the lack of information regarding the mass of the arrow and its drag force, which complicates the problem. The original poster has solved part of the problem but is seeking clarification on the setup for the second part involving air resistance.

hannam
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Homework Statement


a ball makes a free-fall with zero initial
velocity and an arrow with 25 m/s initial velocity is thrown to shoot
this ball at the same time. The ball is initially h=38 m higher than the
arrow.
a) Assume no drag force then how long after does this collision occur?
At what height below ball’s initial position does this collision occur?
b) Assume a constant air drag force at any time instant, which is equal
to Drag Force= 2.2 m where m is the mass of object. For this case,
repeat part a). Take g=9.8 m/s2 for both parts of this and other
questions.



Homework Equations



m.g-2,2m=m.a
h=vo.t+1/2gt^2

The Attempt at a Solution


problem is in b part, i solved a.
mg-2,2m=m.a
a=7,6
h=1/2at^2 =3,8t^2

38-3,8t^2= 25.t -1/2.9,8.t^2
there is an quadratic equation now and i think i should have used another formula, I'm not sure. I appreciate your help :)
 

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The quadratic is OK but you forgot to include the air resistance drag force on the arrow.
 
i couldn't decide whether or not to include drag force on the arrow.because, in the question it says "Drag Force= 2.2 m where m is the mass of object" there is no information about the arrow
 
Balls and arrows are both objects, as I see it..
 
ok i tried that one too but i still have quadratic. how can i find t?
 
Use quadratic equation, you know, if at^2 +bt + c = 0, then t = [-b +/- sq rt (b^2- 4ac)]/2a?
 

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