Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: When is integration good enough

  1. Sep 20, 2011 #1
    When is integration "good enough"

    1. I was attempting to find the surface area of a hemisphere by summing up the surface areas of infinitesimal cylinders (or ribbons) of increasing radii (excluding the top and bottom areas). I wanted to solve this integration problem this way as opposed to using spherical coordinates (or any of the other numerous methods).

    2. The attempt at a Solution.

    My method for solving this problem is exactly the same IBY describes in the following post: https://www.physicsforums.com/showthread.php?t=427695

    Dick explains why this attempted solution is incorrect. By claiming: "It gives you the area of the ribbon if it's vertical (i.e. parallel to the direction dx). If not it ignores the horizontal component. That's not a good enough approximation."

    The value that my attempted solution outputs shows that the solution I tried is incorrect; however, this brought up a question for which I have no understanding. What makes an integration a "good enough approximation"? I had thought that since the ribbons' heights are infinitesimal there would be no problem, but there is. Why, and how would one predict that there would be a problem?

    If dick's explanation is correct, then why does integration ever converge to the area under a curve? For example if one was to find the area of under y=x (a 45 degree line) for any discrete change in x, the rectangles whose sum results in the area under the curve is not quite accurate. Since the change in x ceases to be discrete in integration (it becomes infinitely small), that problem is solved. Why is it not so with the above problem?

    Thank you very much! I appreciate any help I can get.​
  2. jcsd
  3. Sep 20, 2011 #2
    Re: When is integration "good enough"

    Your integral is wrong, you made a change of variables. So the limits a and 0 isn't the same anymore when you made [tex]dx = a\cos\theta d\theta[/tex]

    EDIT: Also, I would use from - a to a. Because when you simplfy the integrand, the limits of integration isn't even aproblem
    Last edited: Sep 20, 2011
  4. Sep 20, 2011 #3
    Re: When is integration "good enough"

    You are correct, and I should have noted that my limits of integration are correct in what I did as opposed to IBY. I did not make that mistake. Even with correct limits of integration, the value it results in is incorrect. My question is what makes that method of integrating not a "good enough" approximation.
  5. Sep 20, 2011 #4
    Re: When is integration "good enough"

    I am not 100% sure myself, but here is the intuition I think I can give you.

    Instead of summing up the horizontal dx, ds sums the curvy part.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook