When Is \( n^4 + 4 \) a Prime Number?

  • Thread starter Thread starter Greg
  • Start date Start date
Click For Summary
SUMMARY

The discussion focuses on determining when the expression \( n^4 + 4 \) yields a prime number for integers \( n > 0 \). Participants, including Opalg, topsquark, kaliprasad, Olinguito, and castor28, provided correct solutions to the problem. The key takeaway is that \( n^4 + 4 \) can be factored into \( (n^2 - 2n + 2)(n^2 + 2n + 2) \), indicating that for \( n > 1 \), the expression is not prime due to both factors being greater than 1. Therefore, the only prime result occurs when \( n = 1 \).

PREREQUISITES
  • Understanding of prime numbers and their properties
  • Familiarity with polynomial factorization techniques
  • Basic knowledge of integer arithmetic
  • Experience with mathematical problem-solving strategies
NEXT STEPS
  • Study polynomial factorization methods in depth
  • Explore properties of prime numbers and their distributions
  • Investigate other expressions that yield prime numbers for specific integer values
  • Learn about mathematical proofs related to prime number generation
USEFUL FOR

Mathematicians, educators, students in number theory, and anyone interested in exploring the properties of prime numbers and polynomial expressions.

Greg
Gold Member
MHB
Messages
1,377
Reaction score
0
Here is this week's POTW:

-----

Given that $n$ is an integer greater than $0$, when is $n^4+4$ prime?

-----

Remember to read the https://mathhelpboards.com/showthread.php?772-Problem-of-the-Week-%28POTW%29-Procedure-and-Guidelines to find out how to https://mathhelpboards.com/forms.php?do=form&fid=2!
 
Physics news on Phys.org
Congratulations to Opalg, topsquark, kaliprasad, Olinguito and castor28 for their correct solutions. castor28's solution may be found below.

We have the polynomial identity:
$$
n^4 + 4 = (n^2 - 2n + 2)(n^2 + 2n + 2)
$$
Where both factors are integers if $n$ is an integer. The second factor is always greater than $1$, and the first one is greater than $1$ if $n>1$, in which case $n^4+4$ is composite. If $n=1$, $n^4+4=5$ is prime.

Therefore, $n^4+4$ is prime if and only if $n=1$.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K